A robber is planning to rob the houses along a street. The constraint is, that he cannot rob adjacent houses. If done, it will alert the police. For the below-given algorithm and input, your task is to draw a DP matrix AND return the maximum earnings in a single night: nums = [4,3,6,2,7,10,5] Algorithm: def rob(self, nums: List[int]) - -> int: dp = [0]*len(nums) // Initialize dp array n = = len(dp) if len(nums) == 1: return nums[0] elif len(nums)==2: return max(nums[0],nums[1]) dp[0]=nums[0] dp[1]=max(nums[1], nums[0]) for i in range(2,len(nums)): dp[i] = max(nums[i]+dp[i-2],dp[i-1]) return dp[n-1]

A robber is planning to rob the houses along a street. The constraint is, that he cannot rob adjacent houses. If done, it will alert the police. For the below-given algorithm and input, your task is to draw a DP matrix AND return the maximum earnings in a single night: nums = [4,3,6,2,7,10,5] Algorithm: def rob(self, nums: List[int]) - -> int: dp = [0]*len(nums) // Initialize dp array n = = len(dp) if len(nums) == 1: return nums[0] elif len(nums)==2: return max(nums[0],nums[1]) dp[0]=nums[0] dp[1]=max(nums[1], nums[0]) for i in range(2,len(nums)): dp[i] = max(nums[i]+dp[i-2],dp[i-1]) return dp[n-1]

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

A robber is planning to rob the houses along a street. The constraint is, that he cannot rob
adjacent houses. If done, it will alert the police.
For the below-given algorithm and input, your task is to draw a DP matrix AND return the
maximum earnings in a single night:
nums = [4,3,6,2,7,10,5]
Algorithm:
def rob(self, nums: List[int]) -> int:
dp = [0]*len(nums) // Initialize dp array
n = len(dp)
if len(nums) == 1:
return nums[0]
elif len(nums) == 2:
return max(nums[0],nums[1])
dp[0]=nums[0]
dp[1]=max(nums[1],nums[0])
for i in range(2,len(nums)):
dp[i] = max(nums[i]+dp[i-2],dp[i-1])
return dp[n-1]

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