Algorithm 2: Divide And Conquer Approach Data: N: Length of the matrix side M: The NxN matrix Result: Returns a local minimum in the given matrix M Function Find.Local_Minimит (Мatriz M): middle_rowE M.length . 2 M[1].length. 2 middle_colunтп + min_cell + Min(Get Min In Row(middle.row), Get_Min_In_Column(middle.column)); next.cell Get_Next Cell(min.cell);
Algorithm 2: Divide And Conquer Approach Data: N: Length of the matrix side M: The NxN matrix Result: Returns a local minimum in the given matrix M Function Find.Local_Minimит (Мatriz M): middle_rowE M.length . 2 M[1].length. 2 middle_colunтп + min_cell + Min(Get Min In Row(middle.row), Get_Min_In_Column(middle.column)); next.cell Get_Next Cell(min.cell);
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Could someone help implement this in python. Would be great to show it for local max too. Just trying to achieve O(n) complexity.
![Algorithm 2: Divide And Conquer Approach
Data: N: Length of the matrix side
M: The NxN matrix
Result: Returns a local minimum in the given matrix M
Function Find_Local_Minimum(Matrix M):
middle_rowt
M.length .
middle_coluтп +
M[1].length.
min_cell +
Min(Get Min In Row(middle_row), Get Min_In Column(middle_column));
next_cell + Get_Next Cell(min_cell);
if next_cell = min_cell then
| return min_cell;
end
else if next_cell.row < middle_row then
if next cell.column < middle_column then
return Find Local Minimum(Top-Left Sub-Matrix);
end
else
return Find Local Minimum(Top-Right Sub-Matrix);
end
end
else
if next cell.column < middle_column then
return Find_Local_Minimum(Bottom-Left
Sub-Matrix);
end
else
return Find Local Minimum(Bottom-Right
Sub-Matrix);
end
end
end](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6cae6682-776b-4a7b-8d27-37163e48a02c%2Fce9f9218-3e0c-4427-843a-75d6ec76f247%2F2swn6ui_processed.png&w=3840&q=75)
Transcribed Image Text:Algorithm 2: Divide And Conquer Approach
Data: N: Length of the matrix side
M: The NxN matrix
Result: Returns a local minimum in the given matrix M
Function Find_Local_Minimum(Matrix M):
middle_rowt
M.length .
middle_coluтп +
M[1].length.
min_cell +
Min(Get Min In Row(middle_row), Get Min_In Column(middle_column));
next_cell + Get_Next Cell(min_cell);
if next_cell = min_cell then
| return min_cell;
end
else if next_cell.row < middle_row then
if next cell.column < middle_column then
return Find Local Minimum(Top-Left Sub-Matrix);
end
else
return Find Local Minimum(Top-Right Sub-Matrix);
end
end
else
if next cell.column < middle_column then
return Find_Local_Minimum(Bottom-Left
Sub-Matrix);
end
else
return Find Local Minimum(Bottom-Right
Sub-Matrix);
end
end
end
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