Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. This time, your problem has additional details: Constraints: The solution set must not contain duplicate triplets. The order of the output and the order of the triplets does not matter. 3 <= nums.length <= 3000 -105 <= nums[i] <= 105 Function definition for Java: public List> threeSum(int[] nums) { // Your code here } Function definition for Python: def threeSum(self, nums: List[int]) -> List[List[int]]: #Your code here Announced Test Cases: Input: nums = [0,1,1] Output: [] Explanation: The only possible triplet does not sum up to 0. Input: nums = [-5,0,5,10,-10,0] Output: [[-10,0,10],[-5,0,5]] Explanation: There are two possible combinations of triplets that satisfy: (-5,0,5) and (-10,0,10). Hint: There are 3 well-known ways to solve this problem!
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. This time, your problem has additional details: Constraints: The solution set must not contain duplicate triplets. The order of the output and the order of the triplets does not matter. 3 <= nums.length <= 3000 -105 <= nums[i] <= 105 Function definition for Java: public List> threeSum(int[] nums) { // Your code here } Function definition for Python: def threeSum(self, nums: List[int]) -> List[List[int]]: #Your code here Announced Test Cases: Input: nums = [0,1,1] Output: [] Explanation: The only possible triplet does not sum up to 0. Input: nums = [-5,0,5,10,-10,0] Output: [[-10,0,10],[-5,0,5]] Explanation: There are two possible combinations of triplets that satisfy: (-5,0,5) and (-10,0,10). Hint: There are 3 well-known ways to solve this problem!
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0.
This time, your problem has additional details:
Constraints:
- The solution set must not contain duplicate triplets.
- The order of the output and the order of the triplets does not matter.
- 3 <= nums.length <= 3000
- -105 <= nums[i] <= 105
Function definition for Java:
public List<List<Integer>> threeSum(int[] nums) {
// Your code here
}
// Your code here
}
Function definition for Python:
def threeSum(self, nums: List[int]) -> List[List[int]]:
#Your code here
#Your code here
Announced Test Cases:
Input: nums = [0,1,1] Output: [] Explanation: The only possible triplet does not sum up to 0.
Input: nums = [-5,0,5,10,-10,0]
Output: [[-10,0,10],[-5,0,5]]
Explanation: There are two possible combinations of triplets that satisfy: (-5,0,5) and (-10,0,10).
Input: nums = [-5,0,5,10,-10,0]
Output: [[-10,0,10],[-5,0,5]]
Explanation: There are two possible combinations of triplets that satisfy: (-5,0,5) and (-10,0,10).
Hint: There are 3 well-known ways to solve this problem!
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