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Permute the loops in the following function so that it scans the three-dimensional array a with a stride-1 reference pattern. 1 int sumarray3d(int a[N][N][N]) 2 ( 3 int i, j, k, sum = 0; 4 5 8 for (i=0;i< N;i++) { for(j=0; j for (k = 0; k< N; k++) { for(j = 0; j

Permute the loops in the following function so that it scans the three-dimensional array a with a stride-1 reference pattern. 1 int sumarray3d(int a[N][N][N]) 2 ( 3 int i, j, k, sum = 0; 4 5 8 for (i=0;i< N;i++) { for(j=0; j for (k = 0; k< N; k++) { for(j = 0; j

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Permute the loops in the following function so that it scans the three-dimensional array a with a stride-1 reference pattern. 1 int sumarray3d(int a[N][N][N]) { int i, j, k, sum = 0; for (i = 0; i < N;i++) { for(j = 0; j<N; j++) { for (k = 0; k< N; k++) { sum += a[k][0][0]; 2 3 4 5 9 10 11 12 13 } } for (k = 0; k< N; k++) { for (i = 0; i< N;i++) { for(j = 0; j<N; j++) { sum += a[k][0][0]; } } } } return sum; for (i = 0; i < N;i++) { for (k = 0; k< N; k++){ } } } } Submit for(j = 0; j<N; j++){ for (i = 0; i < N;i++) { for (j = 0; j<N; j++) { sum += a[k][0]): } for (k = 0; k< N; k++){ sum += a[k][10]: } for (k = 0; k< N; k++) { for(j = 0; j<N; j++) { for (i = 0; i< N;i++) { sum += a[k][0][0]; Request Answer
Transcribed Image Text:Permute the loops in the following function so that it scans the three-dimensional array a with a stride-1 reference pattern. 1 int sumarray3d(int a[N][N][N]) { int i, j, k, sum = 0; for (i = 0; i < N;i++) { for(j = 0; j<N; j++) { for (k = 0; k< N; k++) { sum += a[k][0][0]; 2 3 4 5 9 10 11 12 13 } } for (k = 0; k< N; k++) { for (i = 0; i< N;i++) { for(j = 0; j<N; j++) { sum += a[k][0][0]; } } } } return sum; for (i = 0; i < N;i++) { for (k = 0; k< N; k++){ } } } } Submit for(j = 0; j<N; j++){ for (i = 0; i < N;i++) { for (j = 0; j<N; j++) { sum += a[k][0]): } for (k = 0; k< N; k++){ sum += a[k][10]: } for (k = 0; k< N; k++) { for(j = 0; j<N; j++) { for (i = 0; i< N;i++) { sum += a[k][0][0]; Request Answer
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