Consider the following loop, which is the same loop as in the Free Form part:int low, high, A[100]; //assume array A has been initialized//Precondition: 0 < low S high < 100int best-low, sub-low+1;while (sub <= high){if (A[sub]>A[best])best=sub;++sub;}//Postcondition: A[i]

Answered: sider the following loop, which is the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <iostream> using namespace std; const int ROWS = 10; const int COLS = 10; int generateRND(int MIN, int MAX) { return rand() % (MAX - MIN + 1) + MIN; } void initializeArray(int C[][COLS], int min, int max) { for (size_t i = 0; i < ROWS; i++) { for (size_t j = 0; j < COLS; j++) { C[i][j] = generateRND(min, max); } } } void swap(int A[][COLS], int B[][COLS]) { int temp; for (size_t j = 0; j < COLS; j += 2) { for (size_t j = 0 ; j< COLS; j +=) } } void printArray(int C[][COLS]) { for (size_t i = 0; i < ROWS; i++) { for (size_t j = 0; j < COLS; j++) { cout << C[i][j] << " "; } cout << endl; } } int main() { srand((unsigned)time(0)); int A[ROWS][COLS] = { 0 }; int B[ROWS][COLS] = { 0 }; const int MIN = 2; const int MAX = 50; initializeArray(A, 2, 50); } Declares two 10X10 Two-dimensional arrays A and B of type integer. Each array consists of 100 random integers between 2 and 50. 1. Swaps (exchange) the elements of A with…
This C++ program keeps giving me the wrong median. #include <iostream> using namespace std; double median_value(int* arrptr, int n); class Median { private: int* array; int n; public: void getSizeArray(); void getNumElements(); void displayMedian(); ~Median() { delete[] array; } }; void Median::getSizeArray() { cout << "How big is array?"; cin >> n; } void Median::getNumElements() { array = new int[20]; for (int i = 0; i < n; i++) { cout << "How much "; cin >> *(array + i); } } void Median::displayMedian() { int m = median_value(array, n); cout << m; } int main() { Median showMedian; showMedian.getSizeArray(); showMedian.getNumElements(); showMedian.displayMedian(); return 0; } double median_value(int* arrptr, int n) { double median; if (n % 2 == 0) { median = (*(arrptr + (n / 2)) + *(arrptr + (n / 2 +1))) / 2; } else { //(arrptr[i]+(n/2)) median = *(arrptr + (n / 2)); } return median; }
C++ Coding only put the code where it says solution goes here. Don’t change anything else
rewite usung for loop
Size of the array need not be specified, when A. Initialization is a part of definition B. It is a declaratrion C. It is a formal parameter D. All of these
function Sum(A,left,right) if left > right: return 0else if left = right: return A[left] mid = floor(N/2) lsum = Sum(A,left,mid) rsum = Sum(A,mid+1,right) return lsum + rsum function CreateB(A,N)B = new Array of length 1 B[0] = Sum(A,0,N-1) return B Building on the above, in a new scenario, given an array A of non-negative integers of length N, additionally a second array B is created; each element B[j] stores the value A[2*j]+A[2*j+1]. This works straightforwardly if N is even. If N is odd then the final element of B just stores A[N-1] as we can see in the figure below: (added in image) The second array B is now introducing redundancy, which allows us to detect if there has been a hardware failure: in our setup, such a failure will mean the values in the arrays are altered unintentionally. The hope is that if there is an error in A which changes the integer values then the sums in B are no longer correct and the algorithm says there has been an error; if there were an error in B…
Write a for loop to populate array userGuesses with NUM_GUESSES integers. Read integers using cin. Ex: If NUM_GUESSES is 3 and user enters 9 5 2, then userGuesses is {9, 5, 2}. #include <iostream>using namespace std; int main() { const int NUM_GUESSES = 3; int userGuesses[NUM_GUESSES]; int i; /* Your solution goes here */ for (i = 0; i < NUM_GUESSES; ++i) { cout << userGuesses[i] << " "; } return 0;}
#include <iostream>using namespace std;double median(int *, int);int get_mode(int *, int);int *create_array(int);void getinfo(int *, int);void sort(int [], int);double average(int *, int);int getrange(int *,int);int main(){ int *dyn_array; int students; int mode,i,range;float avrg;do{cout << "How many students will you enter? ";cin >> students;}while ( students <= 0 );dyn_array = create_array( students );getinfo(dyn_array, students);cout<<"\nThe array is:\n";for(i=0;i<students;i++)cout<<"student "<<i+1<<" saw "<<*(dyn_array+i)<<" movies.\n";sort(dyn_array, students);cout << "\nthe median is "<<median(dyn_array, students) << endl;cout << "the average is "<<average(dyn_array, students) << endl;mode = get_mode(dyn_array, students);if (mode == -1)cout << "no mode.\n";elsecout << "The mode is " << mode << endl;cout<<"The range of movies seen is…
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#include <iostream>using namespace std;double median(int *, int);int get_mode(int *, int);int *create_array(int);void getinfo(int *, int);void sort(int [], int);double average(int *, int);int getrange(int *,int);int main(){ int *dyn_array; int students; int mode,i,range;float avrg;do{cout << "How many students will you enter? ";cin >> students;}while ( students <= 0 );dyn_array = create_array( students );getinfo(dyn_array, students);cout<<"\nThe array is:\n";for(i=0;i<students;i++)cout<<"student "<<i+1<<" saw "<<*(dyn_array+i)<<" movies.\n";sort(dyn_array, students);cout << "\nthe median is "<<median(dyn_array, students) << endl;cout << "the average is "<<average(dyn_array, students) << endl;mode = get_mode(dyn_array, students);if (mode == -1)cout << "no mode.\n";elsecout << "The mode is " << mode << endl;cout<<"The range of movies seen is…
] ] has_perfect You are to write a function has "perfect (graph)" that takes in a BIPARTITE graph as its input, and then determintes whether or not the graph has a perfect matching. In other words, it will return the Boolean value True if it has one, and False if it does not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (has perfect({"A" : ["B", "C"], "B" : ["A", "D"], "C" : ["A", "D"], "D" : ["B", "C"]}), has perfect ( {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E": ["B","C","F"], "F":["E"]})) This should return True False Python Python
An array int[] intArray can be initialized during its definition by A.) It can't be initialized B.) by writing int[] intArray = {1.0f}; C.) by writing int[] intArray = {0,1,2}; D.) by writing int[0-10] intArray = {0,1,2,3,4,5,6,7,8,9};

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