K-1 roblem 2. Write a function loss(x, q) to return E ita max(0, x¡ – xa + 1), where x is a 1darray of K floats, q is an integer with <9

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Write a function as seen in the photo. Do NOT use any loops

**Problem 2: Function to Calculate Loss**

Write a function `loss(x, q)` to return 

\[
\sum_{{j=0, j \neq q}}^{K-1} \max(0, x_j - x_q + 1)
\]

where `x` is a 1-dimensional array of `K` floats, and `q` is an integer such that \(0 \leq q \leq K - 1\). Here, \(x_j\) is the \((j + 1)\)-th element of the array `x`.

**Example:**

- If \(s = \text{np.array}([5, 1, 3, 6])\), then `loss(s, 2)` returns `7`. 
  - (Note: \(s[2] = 3\).)

**Python Code Structure:**

```python
1  pass
2  
3  def loss(x, q):
4  
5  s = np.array([5, 1, 3, 6])
6  loss(s, 2)
```

**Explanation:**

The task is to create a function named `loss` that calculates a specific summation formula. The formula iterates over all elements of the provided array `x`, except for the element at index `q`. For each other element \(x_j\), it calculates \(\max(0, x_j - x_q + 1)\) and sums these values. 

The example provided illustrates the function's behavior when invoked with the array `s = np.array([5, 1, 3, 6])` and `q = 2`. The result is `7`, indicating the solution to the summation for this specific case.
Transcribed Image Text:**Problem 2: Function to Calculate Loss** Write a function `loss(x, q)` to return \[ \sum_{{j=0, j \neq q}}^{K-1} \max(0, x_j - x_q + 1) \] where `x` is a 1-dimensional array of `K` floats, and `q` is an integer such that \(0 \leq q \leq K - 1\). Here, \(x_j\) is the \((j + 1)\)-th element of the array `x`. **Example:** - If \(s = \text{np.array}([5, 1, 3, 6])\), then `loss(s, 2)` returns `7`. - (Note: \(s[2] = 3\).) **Python Code Structure:** ```python 1 pass 2 3 def loss(x, q): 4 5 s = np.array([5, 1, 3, 6]) 6 loss(s, 2) ``` **Explanation:** The task is to create a function named `loss` that calculates a specific summation formula. The formula iterates over all elements of the provided array `x`, except for the element at index `q`. For each other element \(x_j\), it calculates \(\max(0, x_j - x_q + 1)\) and sums these values. The example provided illustrates the function's behavior when invoked with the array `s = np.array([5, 1, 3, 6])` and `q = 2`. The result is `7`, indicating the solution to the summation for this specific case.
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