Use Python Write a function, print_perfect_cubes(n), that takes an integer parameter n and prints the perfect cubes starting from 03 = 0 and ending with n3. When n is negative, the function prints nothing; but do not check for this condition with an "if" statement, it is unneccesary; use a for loop that will automatically print nothing when n < 0. Hint for choosing the right range for your for loop: In the general case, when n is not negative, your function will need to print n+1 different values.   For example: Test Result print_perfect_cubes(2) 0 1 8 print_perfect_cubes(5) 0 1 8 27 64 125 print_perfect_cubes(-10)

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