### Loop and Condition-Based User Input Summation#### Problem Statement:Write a program using any type of loop that continually prompts the user for input and sums all user inputs that are divisible by 2. The loop should terminate when the user enters a negative number. Upon termination, the program should output the computed sum once.#### Task Requirements:- Implement a loop for continuous user input.- Identify and sum only those inputs that are divisible by 2.- Terminate the loop upon receiving a negative number input.- Output the sum after loop termination.#### Implementation Details:- Assume all necessary libraries and namespaces are already included.- Focus on the code within the main function, post the `return 0;` statement.### Example Code:Here is an illustrative example in C++:```cppint main() { int sum = 0; int userInput; // Loop to continually ask for user input while (true) { std::cout << "Enter a number: "; std::cin >> userInput; // Check for negative number to terminate loop if (userInput < 0) { break; } // Check if the number is divisible by 2 if (userInput % 2 == 0) { sum += userInput; } } // Output the computed sum std::cout << "The sum of all numbers divisible by 2 is: " << sum << std::endl; return 0;}```##### Explanation of the Code:1. **Initialization:** - `sum` is initialized to zero to store the cumulative total. - `userInput` is declared to capture the user's input.2. **Loop:** - A `while (true)` loop is used for continuous execution until explicit termination. - Inside the loop: - Prompt the user for input. - Check if the input is negative to break the loop. - Verify if the input number is divisible by 2; if true, add it to `sum`.3. **Output:** - After exiting the loop, the final sum is printed to the console.This example demonstrates how to handle continuous user input, apply a conditional check, and compute a running total with loop termination based on specific criteria.

As the language is not specified answer written in c++ language

Write code that uses any type of loop. The code should continually ask for a user input and sums all user inputs that are divisible by 2. The loop should continue until the user enters a negative number. The code should output the sum a single time once user entry has completed. You may assume all libraries and namespaces have been previously written into the code, you are just writing everything that would go inside the main function (beyond the return 0:).

Write code that uses any type of loop. The code should continually ask for a user input and sums all user inputs that are divisible by 2. The loop should continue until the user enters a negative number. The code should output the sum a single time once user entry has completed. You may assume all libraries and namespaces have been previously written into the code, you are just writing everything that would go inside the main function (beyond the return 0:).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

### Loop and Condition-Based User Input Summation

#### Problem Statement:
Write a program using any type of loop that continually prompts the user for input and sums all user inputs that are divisible by 2. The loop should terminate when the user enters a negative number. Upon termination, the program should output the computed sum once.

#### Task Requirements:
- Implement a loop for continuous user input.
- Identify and sum only those inputs that are divisible by 2.
- Terminate the loop upon receiving a negative number input.
- Output the sum after loop termination.

#### Implementation Details:
- Assume all necessary libraries and namespaces are already included.
- Focus on the code within the main function, post the `return 0;` statement.

### Example Code:
Here is an illustrative example in C++:

```cpp
int main() {
int sum = 0;
int userInput;

// Loop to continually ask for user input
while (true) {
std::cout << "Enter a number: ";
std::cin >> userInput;

// Check for negative number to terminate loop
if (userInput < 0) {
break;
}

// Check if the number is divisible by 2
if (userInput % 2 == 0) {
sum += userInput;
}
}

// Output the computed sum
std::cout << "The sum of all numbers divisible by 2 is: " << sum << std::endl;

return 0;
}
```
##### Explanation of the Code:
1. **Initialization:**
- `sum` is initialized to zero to store the cumulative total.
- `userInput` is declared to capture the user's input.

2. **Loop:**
- A `while (true)` loop is used for continuous execution until explicit termination.
- Inside the loop:
- Prompt the user for input.
- Check if the input is negative to break the loop.
- Verify if the input number is divisible by 2; if true, add it to `sum`.

3. **Output:**
- After exiting the loop, the final sum is printed to the console.

This example demonstrates how to handle continuous user input, apply a conditional check, and compute a running total with loop termination based on specific criteria.

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