What is the time complexity of functions foo() and bar() respectively in below given code snippets, given that n is the total size of the input and L and R are Vectors def foo(L, R): S = Vector() for x in L: if x in R: S.add_back(x) return S def bar(L, R): R_hash = HashTable() for r in R: R_hash.insert(r, False) S = Vector() for x in L: if R_hash.contains(x): S.add_back(x) return S O(N^2), O(N) O(N), O(N) O(N^2), O(N^2) O(1), O(N)

What is the time complexity of functions foo() and bar() respectively in below given code snippets, given that n is the total size of the input and L and R are Vectors def foo(L, R): S = Vector() for x in L: if x in R: S.add_back(x) return S def bar(L, R): R_hash = HashTable() for r in R: R_hash.insert(r, False) S = Vector() for x in L: if R_hash.contains(x): S.add_back(x) return S O(N^2), O(N) O(N), O(N) O(N^2), O(N^2) O(1), O(N)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Given array A = [514, 650, 174, 559, 649, 155, 200, 255, 520, 380]. Do the following tasks. a. Create an auxiliary array AUX. Use the hash function hash(element) to help yourself. Element refers to the elements in array A. def hash (element) : index = summation of each digit of (element 8 100) 810 return index [Don't write code for part a. You have to draw and show calculations if there are any] b. Complete the function find(A, AUX, key) that returns the frequency [number of times found] if key is found in A else return -1
Write algorithm GetFact(s, i) pre-cond: s is a string of tokens and i is an index that indicates a starting pointwithin s. post-cond: The output consists of a parsing p of the longest substring s[i], s[i +1], ... , s[j − 1] of s that starts at index i and is a valid factor. The output alsoincludes the index j of the token that comes immediately after the parsed factor.
Check the hashing question and write your own "Pseudocode" : • Given an array A[] and a number x, check for pair in A[] with sum as x
Given two arrays of integers, write a function to find the intersection of the arrays. The intersection should include only distinct elements and the result should be in sorted order. Solve this problem using the hash set approach.
Could you help me the following questions? Sara and her friends said they have discovered a way to get O(1) category performance for both insert and remove in a priority queue. Their description of the data structure and algorithms is as follows: They use an array implementation for the priority queue The index of the array represents the rank of an element – e.g. an element whose rank is 50 will be placed at index 49 Each element is the head node to a linked list – if a new element is inserted into the priority queue with the same rank as another element already in the queue, the new element is added to the linked list at its head Example: If an element “X” with rank 25 exists at index 24, and a new element “Y” also has a rank of 25, the linked list at index 24 is “Y” then “X” When remove is performed, the element at the highest index is removed. If there is more than one node at that index, the node at the head of the linked list there is removed Based on this description of the…
Trace counting sort on the following list L of unordered keys which lie withinthe range [10, 18].L[1:10]: 16 11 18 13 11 12 15 15 18 16
The removeMin operation for both the linked and array implementation of a Minheap is: O O(1) O O(logn) O O(n?) O O(n) O O(nlogn)
In python. Write a LinkedList class that has recursive implementations of the add and remove methods. It should also have recursive implementations of the contains, insert, and reverse methods. The reverse method should not change the data value each node holds - it must rearrange the order of the nodes in the linked list (by changing the next value each node holds). It should have a recursive method named to_plain_list that takes no parameters (unless they have default arguments) and returns a regular Python list that has the same values (from the data attribute of the Node objects), in the same order, as the current state of the linked list. The head data member of the LinkedList class must be private and have a get method defined (named get_head). It should return the first Node in the list (not the value inside it). As in the iterative LinkedList in the exploration, the data members of the Node class don't have to be private. The reason for that is because Node is a trivial class…
Given a circular linked list, implement an algorithm that returns the node at the beginning of the loop.DEFINITIONCircular linked list: A (corrupt) linked list in which a node's next pointer points to an earlier node, soas to make a loop in the linked list.EXAMPLEInput:Output:A -> B -> C -> D -> E -> C [the same C as earlier]C
please do what is says Given a string representing an array/vector/linked-list (your choice, will use array for clarity moving forward) of integers both positive and negative, output all the negative values on the left-hand side of the array and all positive numbers on the right-hand side of the array while maintaining their relative positions. You must do this in linear time and linear space complexity or better, i.e. you cannot scan the entire list multiple times again and again to place the values in an new array. You MUST utilize methods related to QuickSort to receive credit for this problem. We will NOT accept iterative solutions. NOTE: Do NOT sort the array, the elements need to remain in their original relative order. Hint: take a look at the partition function in QuickSort. Case 1: Input 3: 1 -1 2 -2 3 -3 4 -4 5 -5 Output 3: -1 -2-3-4 -5 1 2 3 4 5 Case 2: Input 2: 14 9 -12 -13 -11 4 -4 3 3 9 Output 2: -12 -13 -11…
Why you guy's are copaying and pasting the asnswer do your known.
this is the MD5 hashing for js, how do i do something similar for C++? function hashCode(str){ md5(str);var hash = md5.create();hash.update(str);hash.hex();var hashed = hash.array();var ka ='';for(i=0;i<hashed.length;i++){ka+=String.fromCharCode(hashed[i]);}return ka;}