You are employed in a gene therapy laboratory to test the effectiveness of a vector for correcting the DF508 –CFTR mutation.  The vector uses CRISPR –CAS9 genome editing to correct the mutated gene in situ (CFTR-CRISPR). An Ussing chamber experiment was performed using nasal airway cells obtained from a patient with the DF508 CFTR mutation which were transformed with either a control vector consisting of an inert CRISPR-CAS-9 construct (CONTROL) or the active, gene correcting CRISPR CAS-9 construct (CFTR-CRISPR).  The following transepithelial voltage values were obtained for the drug regimen shown under open circuit and current clamp (injected current of 10mA) conditions: CONTROL   Baseline Amiloride Forskolin Inh172 Vte (mV) -78 -2 -4 -3 DVRt (mV) 8 16 7.5 13 R (W.cm-2) 800 1600 750 1300

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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You are employed in a gene therapy laboratory to test the effectiveness of a vector for correcting the DF508 –CFTR mutation.  The vector uses CRISPR –CAS9 genome editing to correct the mutated gene in situ (CFTR-CRISPR). An Ussing chamber experiment was performed using nasal airway cells obtained from a patient with the DF508 CFTR mutation which were transformed with either a control vector consisting of an inert CRISPR-CAS-9 construct (CONTROL) or the active, gene correcting CRISPR CAS-9 construct (CFTR-CRISPR).  The following transepithelial voltage values were obtained for the drug regimen shown under open circuit and current clamp (injected current of 10mA) conditions:

CONTROL

 

Baseline

Amiloride

Forskolin

Inh172

Vte (mV)

-78

-2

-4

-3

DVRt (mV)

8

16

7.5

13

R (W.cm-2)

800

1600

750

1300

I (mA.cm-2)

98

1

5

2

CFTR-CRISPR

Vte (mV)

-38

-6

-23

-9

DVRt (mV)

9

27

6

11

R (W.cm-2)

900

2700

600

1100

I (mA.cm-2)

42

2

38

8

  1. Calculate the electron flow through CFTR for both “CONTROL” and “CFTR-CRISPR”. Note that 1 Ampere = 1 coulomb.second-1 = 6.24×1018second-1 Give your answer as electrons.cm-2.sec-1 to two decimal places followed by power of 10 magnitude (eg 5.66 x1015would give answers of 5.66 and 15)  

 Control:  1.87 x 1013 

CFTR-CRISPR: 1.87 x 1014 

1. how did they get the answer and show the working 

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