Why is the Fe-Fe3-C phase diagram a metastable phase diagram instead of a true equilibrium phase diagram? (b) Define the following phases that exist in the Fe-Fe3-C phase diagram: (i) austenite, (ii) ferrite, (iii) cementite, (iv) ferrite.
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Why is the Fe-Fe3-C phase diagram a metastable phase diagram instead of a true equilibrium phase diagram? (b) Define the following phases that exist in the Fe-Fe3-C phase diagram: (i) austenite, (ii) ferrite, (iii) cementite, (iv) ferrite.
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- Actually, the carbon in CO2(g) is thermodynamically unstable with respect to the carbon in calcium carbonate(limestone). Verify this by determining the standardGibbs free energy change for the reaction of lime,CaO(s), with CO2(g) to make CaCO3(s).Part 1: (a) Calculate K at 298 K for the following reaction: 2C(graphite) + O₂(g) = 2CO(g) K = 1.25 C(graphite) CO(g) 0₂ (8) Part 2 out of 2 AGⓇ x 10 || 48 (b) Use the equilibrium constant to calculate AG (in kJ) at 298 K for the following reaction: 2HCl(g) + Br₂(1) ⇒ 2HBr(g) + Cl₂(g) K= 2.22 × 10-15 at 298 K AG KJ kJ C mol x 10 0 -137.2 0 kJConsider the equilibrium 21(8) — 12(8) Calculate the standard change in enthalpy, AH AH = 62.25 kJ/mol for l₂(g) and AH, 106.6 kJ/mol for I(g).
- Calculate K for the reaction Ag₂ Q(8) + CO(g) ⇒ 2 Ag(s) + CO₂ (g) given the following information: K = Ag₂ O(s) + H₂ (g) ≥ 2 Ag(s) + H₂O(g) K₁ = 1.01 X 10¹3 H₂ (g) + CO₂ (g) ⇒ H₂ O(g) + CO(g) K2 = 0.7714.Calculate AG° for H20(g) + 02(g) = H2O2 (g) at 595 K, using the following data: H2 (9) + O2 (9) = H2O2(g) K = 3.7 x 1037 at 595 K 2H2 (9) + O2 (9) = 2H2O(g) K = 2.6 × 10® at 595 K AG kJ/mol
- Consider the following equilibrium: 4Ag(s) + O2(g) ---> 2Ag2O(s). At 298 K, the equilibrium constant for this reaction is K = 8.44 X 10^3. What is the change in Gf under standard state conditions for Ag2O(s)?Consider the dissolution of NaBr and NaI. The values provided here will be helpful for answering the following questions. ΔH∘solnΔHsoln∘ (kJ/mol) ΔS∘solnΔSsoln∘ Jmol•KNaBr –0.860 57.0NaI –7.50 74.0 Write a balanced equilibrium equation for the dissolution of NaI in water. Include phases. Which of the following explains why the entropy change is greater for the dissolution of NaI compared to the dissolution of NaBr?Choose one: A. The interactions between bromide ions with other bromide ions is stronger than the interactions between iodide ions with other iodide ions. B. The cation forms stronger ion-dipole networks with water in NaBr than NaI because of the weaker bond to Br.C. The more negative change in enthalpy observed with NaI implies greater dissociation and hence greater entropy.D. Iodide has weaker ion-dipole interactions with…Given the equilibrium constants for the following reactions what is the equilibrium constant K. for the reaction 2 Cu (s) + O2 (g) 2 CuO (s)? 4 Cu (s) +O2 (g) 2 Cu20(s) K1 = 6.29 x 104 2 CuO (s) Cu,0(s) + ½ 02 (g) K2 = 17.3
- 2. The equilibrium constant Kp (in atm) for the dissociation reaction of Cl₂ (g) 2C1 (g) was measured as a function of temperature (in K). A graph of [In Kp] versus [1/T] for this reaction gives a straight line with a slope of -1.427 x 104 and an intercept of 14.51. (a) The value of AH° for this dissociation reaction is? (b) The value of AS° (in J/mol K) for this dissociation reaction is? (c) The value of AG for this dissociation reaction is? (d) Based on the results, please explain whether the reaction is exothermic or endothermic and whether it is spontaneous or non-spontaneous at 25 °C.In a blast furnace, carbon monoxide (CO) is used to reduce ferric oxide (Fe,O3) to metallic iron, with carbon dioxide as a by-product. The equilibrium constant Kp for the redox reaction is 19.9 at 1000 K. If the equilibrium pressure of CO2 is 2.4 atm, how much pressure is exerted by CO? Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g)Write the equilibrium constant for C(s) + 2H2(g) ↔ CH4(g)