Which of the following mechanism(s) will lead to a decrease in heterozygosity? Select all that apply. Multiple correct - genetic drift - migration - positive assortative mating - mutation - negative assortative mating
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- Table 14. Crossing Fl individual with another Fl individual Individual # 213 252 Gender Male Female Wild Type Wings Wild Type Antenna Aristapedia Wings Wild Type Antenna Phenotype Table 15. Composition of F2 generation Character 1: No. of Males No. of ΤΟΤAL Females number Wing Veins Antennae Cleft Cleft Wild Type Wild Type Aristapedia 16 12 Wild Type 9 11 1 10 Aristapedia 11 22 Wild Type 13 15 28 1. Does a trait always go together with another trait in one individual? Yes or No? If yes, identify the traits that go together. If no, explain why not? 2. Based on the data in Table 15, what are the possible genotypes of the FI individuals thal you crossed (see Table 14)? Male parent: Female parent: PhenotypesI'm confused about how I would figure out these two questions as I don't really understand the difference or where to start. What would genotypic frequencies be for Wildrose at pt-8 if it were in equilibrium? and How many individuals (to 2 decimal places) of each genotype would there be from Wildrose at pt-8 if it were in equilibrium?at Tools Add-ons Help Last edit was 22 minutes ago rmal text I UA Calibri 12 | 5 EE E6 Section 4: Monohybrid test cross A monohybrid cross is a mating where alleles of just one gene are tracked in the offspring. A test cross is a mating in which two parents (P generation) are crossed to give F1 (first filial generation) offspring, and then two F1 parents are crossed to give F2 (second filial generation) offspring. By tracking offspring through two generations, a test cross can reveal patterns of inheritance for particular genes. 9. In a cross between a b.ck and a white guinea pig, all members of the F1 generation are black. The F2 generation is made of % black and 4 white guinea pigs. Diagram this cross, and list the genotypes and phenotypes for each generation. !!
- I 2. In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown below. [Yes - it's possible for the same phenotypes to have different genotypes]. Mating Parental Phenotypes 1 2 3 4 spotted/white x striped/orange spotted/white x striped/orange spotted/orange x striped/ white spotted/orange x striped/orange Spotted/ orange 122 812 422 623 Number of progeny Spotted/ Striped / white orange 131 128 0 430 0 637 a. Determine which alleles are dominant and assign a letter to each. Striped / white 133 0 0 0 b. What are the genotypes of each parent in each cross? If more than one genotype is possible, list the alternative possibilities.Part A Why is mimicry evolutionarily advantageous (helpful/beneficial)? U =- E E XA PLAYAn anthropologist discovered that Papa new Guyana tribes that had given up the customs of cannibalism also had an avid aversion to grapefruit . The ability to taste the horridbitterness of PTC present in grapefruit respectively human brain tissue is due to a dominant alial. A small tribe of 637 Papa New Guinea hens was tested by a population geneticists the following results were displayed. Tasters Non-tasters Total Males 171 86 257 Females 337 43 380 Total 508 129 637 A.)Calculate the recessive ally of frequency (i)among males (ii) among females B.) calculate the amount of individuals being homeless sigus for tasting PTC, also the number of heterozygotes individuals and non tasters within the tribe. C.) another tribe still being cannibals trust past the territory of the other tribe they were captured killed and feasted on the brains of 50 PTC tasting males respectively 19 females as to access their abilities seen as a gift from gods.…
- Corn and Mendelian Genetics Red Smooth Red Wrinkled Yellow smooth yellowwrinkled #Expected 25 25 25 25 #observed 29.6 53.4 7.2 9.8 X2 value 0.85 32.26 12.67 9.24 The data above is from genetic tracking two traits inherited in Corn. Use the X2 values provided to find the sum of the X2 for this stimulation. Round your answer to the nearest tenth. Mendelian genetics (Probability value and degree of freedom) Red Smooth. Red Wrinkled. Yellow smooth yellowwrinkled #Expected. 25 25 25 25 #observed. 29.6 53.4 7.2 9.8 X2 value. 0.85 32.26 12.67 9.24 The data above is from genetic tracking two traits inherited in Corn. Based on the data above , you can see that the difference between the expected and predicted outcomes is -- (a) significant or (b) not significant? the predicted is…For the purpose of the assignment, we will refer to XY individuals as male and XX individuals as female. In humans, colorblindness (b) is an example of an X-linked recessive trait. In this problem, a male with colorblindness XbY marries a female who is not colorblind but is a carrier of the colorblindness allele (XXb). Using a Punnett square, determine the genotypic and phenotypic probabilities (as percentages) for their potential offspring. Give the percentages in numbers, without the percent sign, for each genotype and phenotype. Genotypes XX Xxb xbxb XY xby Phenotypes Consider females (XX) individuals only. In the two questions below, I am asking for the % of females, not % of all people. What is the % of females who are not colorblind? What is the% of females who are colorblind? Now consider makes (XX) individuals only. In the two questions below, I am asking for the % ofThe next two questions go together. Again with the llamas that display an extraordinary range of fur colors - individuals are either blue, red, or green. But in this isolated population the epistatic relationships between the A and B loci are different. You mate a homozygous red-furred llama (Parent #1) with a homozygous green-furred llama (Parent #2), and all of the offspring are red. You interbreed these red F1s, and the resulting F2 generation consists of 93 red llamas, 27 blue llamas, and 9 green llamas. Assign the genotypes to a modified 9:3:3:1 ratio. red: blue: green What type of epistasis is acting?
- Imagine a population 528 individual plants. In this population, 4 % of the plants produce red flowers, and 9 % produce pink flowers. The remaining plants produce white flowers. Flower colour is attributed to a single locus with two alleles. Red flowers are produced by plants that are homozygote for the R allele. White flowers are produced by plants that are homozygote for the W allele. Heterozygotes (RW) produce pink flowers. What is the expected (under Hardy-Weinberg equilibrium) number plants producing pink flowers in this population? Round your answer to the closest full number.Figure 19.2 In plants, violet flower color (V) is dominant over white (v). If p = .8 and q = 0.2 in a population of 500 plants, how many individuals would you expect to be homozygous dominant (VV), heterozygous (Vv), and homozygous recessive (vv)? How many plants would you expect to have violet flowers, and how many would have white flowers?About 7% of men in a population are red-green colour blind due to a sex-linked recessive gene. Assuming random mating in the population with respect to colour blindness; c) What percentage of men would be colour blind in the next generation?