Can you please make a conclusion for this? Thank you so much!   Suppose you counted 79 R_ and 33 rr. The total number of individuals you counted, N, is 112. You expect 3/4 to be R_ (84) and 1/4 to be rr (28). Are your results close enough to these ratios for you to accept the null hypothesis—that there is no real difference?   Individual'sPhenotype Observed number Observed Ratio Expected Ratio Expected Number (Observed no. – Expected no.)^2 / Expected number R_ 79 2.8 3 84 (79-84) ^2 = 25/84 = 0.297 rr 33 1.18 1 28 (33-28) ^2 = 25/28 = 0.893  TOTAL: 112       Chi Square Value =  1.19 Degrees of freedom = 1

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Can you please make a conclusion for this? Thank you so much!

 

  • Suppose you counted 79 R_ and 33 rr. The total number of individuals you counted, N, is 112. You expect 3/4 to be R_ (84) and 1/4 to be rr (28). Are your results close enough to these ratios for you to accept the null hypothesis—that there is no real difference?

 

Individual'sPhenotype

Observed number

Observed Ratio

Expected Ratio

Expected Number

(Observed no. – Expected no.)^2 / Expected number

R_

79

2.8

3

84

(79-84) ^2 = 25/84 = 0.297

rr

33

1.18

1

28

(33-28) ^2 = 25/28 = 0.893 

TOTAL:

112

     

Chi Square Value =  1.19

Degrees of freedom = 1

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