The human MN blood type is determined by two codominant alleles (labeled LM and LN). Homozygotes LMLM have M blood group, heterozygotes LMLN. have MN blood group and homozygotes LNLN. have N blood group. The frequency of LM in a population on an Arctic island is 0.65 (value of p). Please compare these three cases and complete them with the requested genotype frequency values (use as many decimals as needed) Case 1 Case 2 Case 3 Random mating takes place in this population and no evolutionary forces are acting on this locus Frequency of M blood group = Frequency of MN blood group = Frequency of N blood group = The inbreeding coefficient for this The inbreeding coefficient for this population is 0.05, but no evolutionary population is 0.1, but no evolutionary forces are acting on this locus forces are acting on this locus Frequency of M blood group = Frequency of M blood group = Frequency of MN blood group = Frequency of N blood group = Frequency of MN blood group = Frequency of N blood group = c) Briefly describe the differences in the values calculated between the three cases and propose reasons for those differences
The human MN blood type is determined by two codominant alleles (labeled LM and LN). Homozygotes LMLM have M blood group, heterozygotes LMLN. have MN blood group and homozygotes LNLN. have N blood group. The frequency of LM in a population on an Arctic island is 0.65 (value of p). Please compare these three cases and complete them with the requested genotype frequency values (use as many decimals as needed) Case 1 Case 2 Case 3 Random mating takes place in this population and no evolutionary forces are acting on this locus Frequency of M blood group = Frequency of MN blood group = Frequency of N blood group = The inbreeding coefficient for this The inbreeding coefficient for this population is 0.05, but no evolutionary population is 0.1, but no evolutionary forces are acting on this locus forces are acting on this locus Frequency of M blood group = Frequency of M blood group = Frequency of MN blood group = Frequency of N blood group = Frequency of MN blood group = Frequency of N blood group = c) Briefly describe the differences in the values calculated between the three cases and propose reasons for those differences
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Step 1: Introduction to Hardy-Weinberg equilibrium
VIEWStep 2: Case 1- Random mating takes place and no evolutionary forces are acting on the locus
VIEWStep 3: Case 2- The inbreeding coefficient is 0.05 but no evolutionary forces are acting on the locus
VIEWStep 4: Case 3- The inbreeding coefficient is 0.1 but no evolutionary forces are acting on the locus
VIEWStep 5: The reasons for differences in the 3 cases
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