I need help understanding how to calculate using the Hardy Weinberg Equilibrium. Please see the attached. Thank you! Question 1Calculate the genotypic and allele frequencies with a given population.70 individuals (6 BB, 50 Bb, 14 bb)a. What is the frequeney of homozygous dominant individuals?b. What is the frequency of homozygous recessive individuals?What is the frequency of heterozygous individuals?d. How many alleles are in the population?e. What is the frequency of the dominant allele?f. What is the frequency of the recessive allele?

Name: I need help understanding how to calculate using the Hardy Weinberg Eq
Uploaded: 2022-12-05T11:51:53.000Z
Channel: Bartleby
Description: I need help understanding how to calculate using the Hardy Weinberg Equilibrium. Please see the attached. Thank you! Question 1Calculate the genotypic and allele frequencies with a given population.70 individuals (6 BB, 50 Bb, 14 bb)a. What is the f

The Hardy Weinberg Equilibrium is used to determine the allelic frequencies in a population. In population with two alleles for a particular gene, the Hardy Weinberg equilibrium states that the sum of frequencies of the two alleles is always 1. a. Homozygous dominant individuals are the ones with genotype BB. They are 6 in number. Frequency of homozygous dominant individuals = No. of homozygous dominant individuals/Total no. of individuals = 6/70 = 0.0857 b. Homozygous recessive individuals are the ones with genotype bb. They are 14 in number. Frequency of homozygous recessive individuals = No. of homozygous recessive individuals/Total no. of individuals = 14/70 = 0.2 c. Heterozygous individuals are the ones with genotype Bb. They are 50 in number. Frequency of heterozygous individuals = No. of heterozygous individuals/Total no. of individuals = 50/70 = 0.714 d. There are 70 individuals, each with two alleles of the gene of concern. So, there are 140 alleles of the gene. The genes are of two types - B or b. e. Frequency of the dominant allele = No. of dominant alleles of the gene in all the individuals/Total no. of alleles Now, the total number of dominant allele B is (6 x 2) + (50 x 1) = 62 (6 individuals have 2 B alleles each and 50 have 1 B allele each) So, Frequency of dominant allele = 62/140 = 0.4429 f. Frequency of recessive allele = No. of recessive alleles of the gene in all the individuals/Total no. of alleles Now, the total number of recessive allele b is (14 x 2) + (50 x 1) = 78 (14 individuals have 2 b alleles each and 50 have 1 b allele each) So, Frequency of recessive allele = 78/140 = 0.5571 So, according to Hardy Weinberg equilibrium, if frequency of allele B is p and that of allele b is q, then, p + q = 0.4429 + 0.5571 = 1. Thus the conditions for Hardy Weinberg equilibrium are satisfied. a. Frequency of homozygous dominant individuals = 0.0857 b. Frequency of homozygous recessive individuals = 0.2 c. Frequency of heterozygous individuals = 0.714 d. Total no. of alleles is 140 alleles of two types. e. Frequency of the dominant allele = 0.4429 f. Frequency of recessive allele = 0.5571