You perform a cross between two plants, one MmPp and one mmpp, and obtain offspring with the following phenotypes: 42 MP; 374 Mp; 367 mP; 27 mp. What can you conclude from these data? Group of answer choices The M and P genes are on different chromosomes The recombinant progeny are mP and Mp The M and P genes are far apart on the same chromosome The recombinant progeny are MP and mp
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You perform a cross between two plants, one MmPp and one mmpp, and obtain offspring with the following
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- You cross two plants and get the following results: Recombinant progeny type A: 43 Recombinant progeny type B: 51 Nonrecombinant progeny type C: 129 Nonrecombinant progeny type D: 135 What is the recombination frequency? (Enter your answer as a % without the sign. For example, if your answer is 0.534, you would enter 53.4)You have already localized the genes to the same chromosome by deletion mapping, and now decide that the best way to accomplish the mapping is to conduct two simultaneous three-point testcross experiments. The genes you are investigating are as follows: N = round leaves, n = notched leaves; H = smooth stems, h = hairy stems; R = purple flowers, r = red flowers; B = grey seeds, b = black seeds; and Y = green pods, y = yellow pods. Earlier experiments you have done already established that gene B is in the middle of this gene cluster, so you design both three-point test crosses to include that gene. Cross #1 is designed as RrHhBb x rrhhbb while cross #2 is NnBbYy x nnbbyy. The results of both crosses are given in the table below. Based on the information given, determine the arrangement of these five genes including the position of each allele in the heterozygous fly and the distances between each pair of genes. (Hint: treat each experiment separately, knowing that gene B is in the…The result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. • D-Q: o D-L: | o Q-L: | - L L I L L cM CM Alleles CM Ơ Ơ o Q o d D D d d d # 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 cm. 64 28 62 106 81
- Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?Below are the results from a 3 gene testcross between an XxYyZz plant and an xxyyzz plant: Testcross outcome: XYZ 365 xyz 367 xYz 110 XyZ 105 XYZ 3 Xyz 4 XYZ 25 xyZ 21 1. Determine the order of these genes on the chromosome. Indicate them on the diagram below. 2. Calculate the map distances between the genes (give you answer as map units). Indicate these distances on the diagram above. 3. Determine the coefficient of coincidence. 4. Determine the interference among these genes.Part A: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be AB? Enter your answer as a decimal to three places (for example: 0.120). Part B: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be Ab? Part C: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be aB? Part D: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a signal plant will be ab?
- Arabidopsis thaliana is a diploid plant model organism with 2n = 10. Please select the number options to match the following: %3D number of copies of each gene an Arabidopsis thaliana leaf cell has 1 v number of chromosomes an Arabidopsis thaliana leaf cell contains 1. two 2. five number of chromosomes an 1 v Arabidopsis thaliana gamete cell contains 3. ten pairs of homologous chromosomes an Arabidopsis thaliana leaf cell contains 2.In letter B: If the map distance equals the number of recombinant/total of offspring, wouldn't it be 24/806 x 100? Wouldn't we add both recombinants? Can you explain letter C? I don't grasp that concept well. And since I'm using my question already, would you be able to answer D. Thank you!Two genes on chromosome 7 of corn are glossy (g) for leaf texture and ramosa (r), which determines how the ears branch. A test cross between a heterozygous plant for both loci and a doubly recessive plant produces the following progeny and genotypes Phenotype Number of corn kernels counted GR / gr 46 G r / gr 125 g r / gr 45 g R / gr 121 What is the recombination frequency (in %) for the two loci? ___
- Three linked genes (v, p and b) are studied to begin a genetic map. Crosses were carried out and 10,000 progeny were analyzed for each cross. Of 10,000 progeny, there were: 2207 recombinants between v and p 1489 recombinants between p and b 718 recombinants between b and v Use this information to determine the order of these genes on the chromosome (i.e. construct a genetic map)In an electrophoretic gel across which is applied a powerful electrical alternating pulsed field, the DNA of the haploid fungus Neurospora crassa (n = 7) moves slowly but eventually forms seven bands, which represent DNA fractions that are of different sizes and hence have moved at different speeds. These bands are presumed to be the seven chromosomes. How would you show which band corresponds to which chromosome?Please explain how I can solve this. Thank you You wanted to draw a linkage map for three genes in the fruit fly (A, B, C) that you suspect are linked. You have done a three-point testcross and found that out of the 1500 progeny in the cross, 612 are a · b · c, 603 are A · B · C, 93 are a · B · C, 85 are A · b · c, 53 are a · b · C, 47 are A · B · c, 5 are A · b · C, and 2 are a · B · c. From this data, you can deduce that the genes are linked and the distance between B and C is:
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