When Galileo Galilei rolled a ball down an inclined plane, it traveled 2 meters in the first second, and a total of 8 meters in the first two With vo = 0, what was its acceleration on this inclined plane? 0 meter per second2 0 meters per second2 0 meters per second2 0 meters per second2 0 meters per second2

When Galileo Galilei rolled a ball down an inclined plane, it traveled 2 meters in the first second, and a total of 8 meters in the first two With vo = 0, what was its acceleration on this inclined plane? 0 meter per second2 0 meters per second2 0 meters per second2 0 meters per second2 0 meters per second2

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter14: Instrumentation In Diagnostic Ultrasound

Section: Chapter Questions

Problem 3P

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When Galileo Galilei rolled a ball down an inclined plane, it traveled 1.0 meters in the first second, and a total of 4.0 meters in the first two seconds. What was its acceleration on this inclined plane? 2.0 meters per second2 3.0 meters per second2 4.0 meters per second2 5.0 meters per second2 6.0 meters per second2
Based on the acceleration in the above ball rolling down an inclined plane (with vo = 0 meters per second), how far would it have traveled along the inclined plane in the first six seconds of rolling? 9 meters 16 meters 25 meters 36 meters 49 meters
When Galileo Galilei pushed a ball down an inclined plane, it had an initial velocity (vo) of 4.0 meters per second (time = 0 seconds) and a final velocity (vf) of 10.0 meters per second (time = 2 seconds). How far did the ball travel along the inclined plane in these 2 seconds? 14 meters 20 meters 28 meters 40 meters 84 meters
Rotate the ball horizontally on an 80 cm long non-stretchable cord with angular velocity of 3 s^(-1). After ten seconds of clockwise rotation, the cord breaks. At what speed and in what direction does the ball fly, if it was faced north at time t = Os? Where and after how much time does the ball land on the ground that is 1 m below the plaine in which we rotate the string? {Solution: v= (0.37 m/s,2.37 m/s); d=1.07 m, t=0.447 s.) }
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