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- The bronze bar 5 m long with a cross sectional area of 425 mm² is placed between two rigid walls as shown in the Figure. At a temperature of -20°C, the gap A = 3.8 mm. Find the temperature at which the compressive stress in the bar will be 35 MPa. Use a = 18.0 x 10-6 m/(m-°C) and E = 80 GPa. L AThe bronze bar 3.00 m long with a cross-sectional area of 350 mm is placed between two rigid walls. At a temperature of – 20 °C, there is a gap of 2.20 mm. Find the temperature at which the compressive stress in the bar will be 30 MPa. Use a = 18x10/°C and E = 80 GPa. L = 3.0 m 2.20 mm2.75 A steel rod is stretched between two walls. At 20°C, the tensile force in the rod is 5000 N. If the stress is not to exceed 130 MPa at –20°C, find the minimum allowable diameter of the rod. Use a = 11.7 × 10–6/°C and E = 200 GPa. %3D
- Question 7 The bronze bar 3 m long with a cross-sectional area of 350 mm? is placed between two rigid walls. At a temperature of -20°C, there is a gap A = 2.2 mm, as shown in the figure. Find the temperature at which the compressive stress in the bar will be 30 MPa. Use a = 18.0 x 106 /°C and E = 80 GPa. 3 m-The bronze bar 3 m long with a cross-sectional area of 350 mm2 is placed between two rigid walls. At a temperature of -20°C, there is a gap A = 2.2 mm, as shown in the figure. Find the temperature at which the compressive stress in the bar will be 30 MPa. Use a = 18.0x 10-6 / °C and E = 80 GPa. 3 m-3. A rigid block of mass M is supported by three symmetrically spaced rods as shown in the figure. Each copper rod has an area of 900 mm²; E = 120 GPa; and the allowable stress is 70 MPa. The steel rod has an area of 1200 mm²; E = 200 GPa; and the allowable stress is 140 MPa. Determine the largest mass M which can be supported. Copper 160 mm M Steel 240 mm Copper 160 mm
- A tapered cantilever beam AB having rectangular cross sections is subjected to a concentrated load P = 46 lb and a couple Mo = 790 lb - in. acting at the free end [see the figure part (a)). The width b of the beam is constant and equal to 1.0 in., but the height varies linearly from ha = 2.0 in. at the loaded end to hp = 3.0 in. at the support. Use L = 20 in. Мо В hg (a) 3P qo = T Мо (b) ЗР 90 =7 \ Mo.Knowing that the couple shown acts in a vertical plane, determine the stress at (a) point A, (b) point B. (a) GA= (b) B = +201 B. 40 20 Dimensions in mm MPa MPa 20 80 20 T N M = 12 kN - mFor the stress block shown, what is OP2 if OP1 = 140 MPa (T)? A.60 MPa (T) 40 MPa B.60 MPa (C) C.20 MPa (C) D.20 MPa (T) Txy Which among the following is ALWAYS TRUE about the maximum in-plane shear stress? A.It acts on planes 450 from principal planes. B.It is equal to the absolute maximum shear stress. C.It is equal to the principal stress with higher magnitude. D.It acts on planes with zero normal stress. 120 MPa
- The cross-sectional area of bar ABCD is 600 mm². Determine the maximumnormal stress in the bar.2. A steel shaft (G = 80 GPa) of total length L = 3.0 m is encased for one-third of its length by a brass sleeve (G, = 40 GPa) that is securely bonded to the %3D %3D steel. The outer diameters of the shaft and sleeve are di = 75 mm and d2 = 90 mm, respectively. The maximum shear stress in brass is 70 MPa, maximum shear stress in steel is 110 MPa and the maximum allowable angle of twist is 5°. What is the maximum allowable torque that can be applied at the ends of the shaft? Brass Steel shaft di = 75 mm d2 = 90 mm sleeve T T A B 1.0 m- L = 2.0 m- 2 = 2.0 m d1 dy Brass- sleeve Steel shaft d2 d2Q1/a. At a point in a given material the three dimensional state of stress is given by Ox=oy=oz=10 MPa, txy=20 MPa, tyz= 40Mpa, TXZ= 10 MPa. Compute the principle planes if the corresponding principles stresses are, 01=37.3 MPa , 02= - 10MPA, o3=2.7 MPa b) What are the equation of equilibrium in cartizian coordinate of stressed body