What is the Eº for the cell: L | L2+ (aq) || T²+(aq) | T? Final answer: two decimal places; include negative sign whenever applicable; no unit necessary. Use data given in Table 1. Table 1. Standard Reduction Potentials at 25°C of Some Hypothetical Substances A3+ + 3e → A Eº = + 1.4 V Eº = -2.87 V Eº = + 0.77 V Eº = + 0.54 V x2+ + 2e → X R³+ + eR2+ J2 +2e → 2J" L2+ + 2e → L T2+ + 2e → T Eº = -1.91 V Eº = -0.93 V

What is the Eº for the cell: L | L2+ (aq) || T²+(aq) | T? Final answer: two decimal places; include negative sign whenever applicable; no unit necessary. Use data given in Table 1. Table 1. Standard Reduction Potentials at 25°C of Some Hypothetical Substances A3+ + 3e → A Eº = + 1.4 V Eº = -2.87 V Eº = + 0.77 V Eº = + 0.54 V x2+ + 2e → X R³+ + eR2+ J2 +2e → 2J" L2+ + 2e → L T2+ + 2e → T Eº = -1.91 V Eº = -0.93 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following standard reduction potentials. O₂(g) + 2H₂O(1) +4 Ca²+ (aq) +2e - 40H (aq) E° = 0.401 V Ca(s) E= -2.868 V E°
Consider the cell described below. Al | Al³+ (1.00 M) || Pb²+ (1.00 M) | Pb Calculate the cell potential after the reaction has operated long enough for the [A13+] to have changed by 0.46 mol/L. (Assume T= 25°C.) V Need Help? Read It Supporting Materials Periodic Table Watch It Constants & Factors Supplemental Data
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2. In the electrolysis of an aqueous Zn(NO3)2 solution, what reactions occur at the anode and at the cathode, assuming standard conditions? O, + 4H + 4e → 2H;O 6° = 1.23 V 2H,0 + 2e → H2 + 20H E° = -0.83V Zn2 + 2e → Zn ɛ° = -0.76 V NO, + 4H + 3e' → NO + 2H20 E° = 0,96 V ANODE: CATHODE:
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Consider the following voltaic cellat 25°C: Al(s) | Al3*(0.20 M, aq) || Al3+(0.75 M, aq) | Al(s) If the standard reduction potential for the Al3+(aq) /Al(s) redox couple is -1.66 V, what is the overall cell reaction and the cell potential of the voltaic cell shown above? (Reference the cell as written above.) The overall cell reaction is Al3+(0.75 M, aq) AIS*(0.20 M, ag) and E°cell = +0.0113 V. There is no overall cell reaction and E°cell = 0.00 V. The overall cell reaction is Al3+(0.20 M, aq) Als*(0.75 M, aq) and E°cell = +0.0113 V. The overall cell reaction is Al3+(0.20 M, aq) →A13+(0.75 M, ag) and E°cell| = -0.0113 V. The overall cell reaction is Al3*(0.75 M, aq) →AI3*(0.20 M, aq) and E°cell = -0.0113 V. None of these
half-reaction standard reduction potential Br,(1)+2e - 2 Br (aq) =+1.065 V red MnO, (aq)+2 H,0(1)+3e MnO,(5)+4 OH (aq) E° =+0.59 V (red Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you have enough information to Yes calculate the cell voltage under standard No conditions? If said it was you possible to calculate the cell voltage, do so and enter your answer here. Round your Ov answer to 2 significant digits.
Calculate the cell potential of a voltaic cell given the following standard potentials: X -> X2+ + 2 e- Eo = -1.69 V Y3+ -> + 3 e- -> Y Eo = 0.94 V Note: Answer in 2 decimal places.
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