Consider the following half-reactions along with their respective standard reduction potential. Which of the species will react with Hg)spontaneously? E° = +1.22 V Mn02(s) + 4Hag) + 2e → Mna) + 2H,0) E° = +0.61 V Hg,SO46) + 2e¯→ 2Hg + SOaq) E° = -0.95 V Sn0z(s) + 2H,0m + 4e → Sns) + 40HTag) E° = -1.48 V Cr(OH)3(G) + 3e Cr + 30HTag) O Sno2(s) O Cr(OH)3(3) O Snoza) and Cr(0H)3(2) O MnO2(s)
Consider the following half-reactions along with their respective standard reduction potential. Which of the species will react with Hg)spontaneously? E° = +1.22 V Mn02(s) + 4Hag) + 2e → Mna) + 2H,0) E° = +0.61 V Hg,SO46) + 2e¯→ 2Hg + SOaq) E° = -0.95 V Sn0z(s) + 2H,0m + 4e → Sns) + 40HTag) E° = -1.48 V Cr(OH)3(G) + 3e Cr + 30HTag) O Sno2(s) O Cr(OH)3(3) O Snoza) and Cr(0H)3(2) O MnO2(s)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Consider the following half-reactions along with their respective standard reduction potential. Which of the species
will react with Hg)spontaneously?
E° = +1.22 V
Mn02(s) + 4Hag) + 2e → Mna) + 2H,0)
E° = +0.61 V
Hg,SO46) + 2e¯→ 2H91 + SOaq)
E° = -0.95 V
Sn0) + 2H,0m + 4e- → Sn) + 40HTag)
E° = -1.48 V
Cr(OH)3(2) + 3e → Cre) + 30Haq)
O Sn02(s)
O Cr(0H)3(3)
O Sno2(s) and Cr(0H)3(s)
O Mn02(3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed410266-a4f3-4f30-8075-c531b94acc9f%2F303d538c-8ba7-4f66-b5b9-4cfdf0933b89%2F9p7i0j9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following half-reactions along with their respective standard reduction potential. Which of the species
will react with Hg)spontaneously?
E° = +1.22 V
Mn02(s) + 4Hag) + 2e → Mna) + 2H,0)
E° = +0.61 V
Hg,SO46) + 2e¯→ 2H91 + SOaq)
E° = -0.95 V
Sn0) + 2H,0m + 4e- → Sn) + 40HTag)
E° = -1.48 V
Cr(OH)3(2) + 3e → Cre) + 30Haq)
O Sn02(s)
O Cr(0H)3(3)
O Sno2(s) and Cr(0H)3(s)
O Mn02(3)
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