A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when Ecell is 1.08 V and [Mn2+] = 0.334 M. Use reduction potential values of Mn2+ = −1.18 V and for Pb2+ = −0.13 V.

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A voltaic cell consists of an Mn/Mn²⁺ half-cell and a Pb/Pb²⁺ half-cell. Calculate [Pb²⁺] when E_cell is 1.08 V and [Mn²⁺] = 0.334 M. Use reduction potential values of Mn²⁺ = −1.18 V and for Pb²⁺ = −0.13 V.

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