y Questions| bartlebyataFe3+ (aq) + 3e Fe (s)-0.0372H+ (aq) + 2e H2 (g)0.0002H20 (I) + 2e H2 (g) + 20H (aq)-0.8277H202 (aq) + 2H+ (aq) + 2e → 2H20 (1)1.776I2 (s) + 2e- → 21- (aq)0.53552103 (aq) + 12H+ (aq) + 10e I2 (s) + 6H20 (1)1.195Mg2+(aq) + 2e → Mg (s)-2.372Mn2+ (aq) + 2e Mn (s)-1.185MnO2 (s) + 4H+ (aq) + 2e Mn2+ (aq) + 2H2O (I)1.224MnO4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H20 (I)1.507Mn04 (aq) + 2H20 (1) + 3e- MnO2 (s) + 4OH- (aq)0.595HNO2 (aq) + H+ (aq) + e- → NO (g) + H20 (1)0.983N2 (g) + 4H20 (1) + 4e¯ → 40H- (aq) + N2H4 (aq)-1.16NO3 (aq) + 4H+ (aq) + 3e → NO (g) + 2H2O (I)0.957Nat (aq) + e → Na (s)-2.71-0.257Ni2+ (aq) + 2e Ni (s)02 (g) + 4H+ (aq) + 4e¯ - 2H2O (I)1.2290.401O2 (g) + 2H20 (I) + 4e¯ → 40H (aq)0.69502 (g) + 2H+ (aq) + 2e¯ → H2O2 (aq)-0.1262Pb2+ (aq) + 2e → Pb (s)-0.3588PbSO4 (s) + H+ (aq) + 2e¯ - Pb (s) + HSO4 (aq)AccessibilityO 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use | PrivacyacBook Air A certain half-reaction has a standard reduction potential E=+1.34 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that mustprovide at least 1.20 V of electrical power. The cell will operate under standard conditions.Note for advanced students: assume the engineer reguires this half-reaction to happen at the anode of the cell.nh DataHalf-ReactionE° (V)0.7996Is there a minimum standard reductionpotential that the half-reaction used atthe cathode of this cell can have?= OvAg+ (aq) + e- -→ Ag (s)O yes, there is a minimum.E%3DredAl3+ (aq) + 3e- → Al (s)-1.6761.692Au+ (aq) + e → Au (s)If so, check the "yes" box and calculatethe minimum. Round your answer to 2decimal places. If there is no lowerlimit, check the "no" box.O no minimumAu3+ (aq) + 3e- → Au (s)1.498Ba2+ (ag) + 2e- - Ba (s)-2.912Brz (1) + 2e2Br (aq)1.066-Ca2+ (ag) + 2e Ca (s)-2.868Is there a maximum standard reductionpotential that the half-reaction used atthe cathode of this cell can have?O yes, there is a maximum.E"red= OvCl2 (9) + 2e - 2CI- (aq)1.35827Co2+ (aq) + 2e- - Co (s)Co3+ (aq) + e- → Co2+ (aq)Cr2+ (aq) + 2e Cr (s)Cr3+ (aq) + 3e- - Cr (s)Cr3+ (aq) + e Cr2+ (aq)-0.28If so, check the "yes" box and calculatethe maximum. Round your answer to 2decimal places. If there is no upperlimit, check the "no" box.1.92O no maximum-0.913-0.744-0.407By using the information in the ALEKSData tab, write a balanced equationdescribing a half reaction that could beused at the cathode of this cell.Cro42- (aq) + 4H20 (I) + 3e Cr(OH)3 (s) + 50H- (aq)-0.13Cu2+ (aq) + 2e- - Cu (s)Cu2+ (aq) + e Cu+ (aq)Cut (aq) + e - Cu (s)0.34190.153Note: write the half reaction as it wouldactually occur at the cathode.0.521F2 (9) + 2e 2F (aq)2.866Fe2+ (aq) + 2e - Fe (s)-0.447ExplanationCheckFe3+ (aq) + e Fe2+ (aq)0.771MacBook AirD00D00F12escF8F9F10F11F4F5F6F7F1F2@232$%&6.9

Answered: Image /qna-images/answer/e5734cb8-2946-40be-b962-20b7e9192b98.jpg

A certain half-reaction has a standard reduction potential E-+1.34 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.20 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. pa Data Half-Reaction E° (V) Ag+ (aq) + e Ag (s) 0.7996 Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a minimum. %3! red = Ov Al3+ (aq) + 3e- - Al (s) -1.676 1.692 If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Au+ (aq) + e Au (s) O no minimum Au3+ (aq) + 3e Au (s) 1.498 Ba2+ (aq) + 2e" - Ba (s) -2.912 Brz (1) + 2e- 2Br (aq) 1.066 Ca2+ (aq) + 2e-- Ca (s) -2.868 Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a maximum. E red = Iv %3D Cl2 (g) + 2e- Co2+ (aq) + 2e- Co (s) 2CI- (aq) 1.35827 --0.28 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. Co3+ (aq) + e - Co2+ (aq) 1.92 O no maximum Cr2+ (aq) + 2e - Cr (s) Cr3+ (aq) + 3e- Cr (s) -0.913 -0.744 Cr3+ (aq) + e Cr2+ (aq) --0.407 By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cro42- (aq) + 4H20 (1) + 3e" Cr(OH)3 (s) + 50H (aq) -0.13 Cu2+ (aq) + 2e + Cu (s) 0.3419 Cu2+ (aq) + e- - Cut (aq) 0.153 Note: write the half reaction as it would actually occur at the cathode. Cu+ (aq) + e - Cu (s) 0.521 1. F2 (9) + 2e 2F (aq) 2.866 Fe2+ (aq) + 2e- Fe (s) -0.447

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...