A certain half-reaction has a standard reduction potential E=-0.44 V. An engineer proposes using thH red provide at least 1.20 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of th dla Data Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a minimum. %3D red If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. no minimum Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? yes, there is a maximum. %3! red check the "yes" box and calculate so, the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. If no maximum By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cr Note: write the half reaction as it would actually occur at the cathode. Explanation Check

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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olo Data
Fe3+ (aq) + 3e Fe (s)
-0.037
2H (aq) + 2e-- H2 (g)
0.000
2H20 (1) + 2e H2 (g) + 20H (aq)
-0.8277
H202 (aq) + 2H+ (aq) + 2e¯ → 2H2O (I)
1.776
I2 (s) + 2e¯ – 21- (aq)
0.5355
2103 (aq) + 12H (aq) + 10e¯ → I2 (s) + 6H2O (I)
1.195
Mg2+ (aq) + 2e→ Mg (s)
-2.372
Mn2+ (ag) + 2e → Mn (s)
-1.185
MnO2 (s) + H+ (aq) + 2e¯ → Mn2+ (aq) + 2H2O (I)
1.224
Mn04 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I)
1.507
MnO4- (aq) + 2H2O (I) + 3e → MnO2 (s) + 40H (aq)
0.595
HNO2 (aq) + H+ (aq) + e → NO (g) + H20 (1)
0.983
N2 (g) + 4H2O (1) + 4e → 40H (aq) + N2H4 (aq)
-1.16
NO3- (aq) + 4H+ (aq) + 3e → NO (g) + 2H2O (1)
0.957
-2.71
Na+ (ag) + e → Na (s)
Ni2+ (aq) + 2e → Ni (s)
-0.257
02 (g) + 4H+ (aq) + 4e¯ 2H20 (1)
+ 40H (aq)
1.229
0.401
02 (9) + 2H20 (I) + 4e¬
0.695
02 (g) + 2H+ (aq) + 2e → H2O2 (aq)
-0.1262
Pb2+ (aq) + 2e Pb (s)
MacBook Air
F12
F11
F10
F8
F7
&
*
delete
8
Transcribed Image Text:olo Data Fe3+ (aq) + 3e Fe (s) -0.037 2H (aq) + 2e-- H2 (g) 0.000 2H20 (1) + 2e H2 (g) + 20H (aq) -0.8277 H202 (aq) + 2H+ (aq) + 2e¯ → 2H2O (I) 1.776 I2 (s) + 2e¯ – 21- (aq) 0.5355 2103 (aq) + 12H (aq) + 10e¯ → I2 (s) + 6H2O (I) 1.195 Mg2+ (aq) + 2e→ Mg (s) -2.372 Mn2+ (ag) + 2e → Mn (s) -1.185 MnO2 (s) + H+ (aq) + 2e¯ → Mn2+ (aq) + 2H2O (I) 1.224 Mn04 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I) 1.507 MnO4- (aq) + 2H2O (I) + 3e → MnO2 (s) + 40H (aq) 0.595 HNO2 (aq) + H+ (aq) + e → NO (g) + H20 (1) 0.983 N2 (g) + 4H2O (1) + 4e → 40H (aq) + N2H4 (aq) -1.16 NO3- (aq) + 4H+ (aq) + 3e → NO (g) + 2H2O (1) 0.957 -2.71 Na+ (ag) + e → Na (s) Ni2+ (aq) + 2e → Ni (s) -0.257 02 (g) + 4H+ (aq) + 4e¯ 2H20 (1) + 40H (aq) 1.229 0.401 02 (9) + 2H20 (I) + 4e¬ 0.695 02 (g) + 2H+ (aq) + 2e → H2O2 (aq) -0.1262 Pb2+ (aq) + 2e Pb (s) MacBook Air F12 F11 F10 F8 F7 & * delete 8
A certain half-reaction has a standard reduction potential E=-0.44 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must
provide at least 1.20 V of electrical power. The cell will operate under standard conditions.
Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.
nh Data
Is there a minimum standard reduction
potential that the half-reaction used at
the cathode of this cell can have?
Half-Reaction
E° (V)
yes, there is a minimum.
= Ov
red
Ag+ (aq) + e- → Ag (s)
0.7996
Al3+ (aq) + 3e- → Al (s)
If so, check the "yes" box and calculate
the minimum. Round your answer to 2
decimal places. If there is no lower
limit, check the "no" box.
-1.676
Au+ (aq) + e- - Au (s)
Au3+ (aq) + 3e - Au (s)
O no minimum
1.692
1.498
Ba2+ (aq) + 2e - Ba (s)
-2.912
Br2 (1) + 2e- - 2Br (aq)
1.066
Is there a maximum standard reduction
potential that the half-reaction used at
the cathode of this cell can have?
E = Ov
red
O yes, there is a maximum.
Ca2+ (aq) + 2e + Ca (s)
-2.868
Cl2 (g) + 2e -→ 2CI- (aq)
1.35827
If so, check the "yes" box and calculate
the maximum. Round your answer to 2
decimal places. If there is no upper
limit, check the "no" box.
Co2+ (aq) + 2e-- Co (s)
Co3+ (aq) + e- - Co2+ (aq)
Cr2+ (aq) + 2e-- Cr (s)
Cr3+ (aq) + 3e- → Cr (s)
-0.28
O no maximum
1.92
-0.913
-0.744
-0.407
Cr3+ (aq) + e- Cr2+ (aq)
By using the information in the ALEKS
Data tab, write a balanced equation
describing a half reaction that could be
used at the cathode of this cell.
-0.13
Cro42- (aq) + 4H20 (1) + 3e Cr(OH)3 (s) + 50H (aq)
0.3419
Cu2+ (ag) + 2e Cu (s)
Note: write the half reaction as it would
actually occur at the cathode.
0.153
Cu2+ (aq) + e - Cu+ (aq)
0.521
Cu+ (aq) + e - Cu (s)
2.866
F2 (g) + 2e - 2F (aq)
-0.447
Fe2+ (aq) + 2e-- Fe (s)
Explanation
Check
0.771
Fe+ (aq) + e- Fe2+ (aq)
MacBook A
FZ
Transcribed Image Text:A certain half-reaction has a standard reduction potential E=-0.44 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.20 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. nh Data Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? Half-Reaction E° (V) yes, there is a minimum. = Ov red Ag+ (aq) + e- → Ag (s) 0.7996 Al3+ (aq) + 3e- → Al (s) If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. -1.676 Au+ (aq) + e- - Au (s) Au3+ (aq) + 3e - Au (s) O no minimum 1.692 1.498 Ba2+ (aq) + 2e - Ba (s) -2.912 Br2 (1) + 2e- - 2Br (aq) 1.066 Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? E = Ov red O yes, there is a maximum. Ca2+ (aq) + 2e + Ca (s) -2.868 Cl2 (g) + 2e -→ 2CI- (aq) 1.35827 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. Co2+ (aq) + 2e-- Co (s) Co3+ (aq) + e- - Co2+ (aq) Cr2+ (aq) + 2e-- Cr (s) Cr3+ (aq) + 3e- → Cr (s) -0.28 O no maximum 1.92 -0.913 -0.744 -0.407 Cr3+ (aq) + e- Cr2+ (aq) By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. -0.13 Cro42- (aq) + 4H20 (1) + 3e Cr(OH)3 (s) + 50H (aq) 0.3419 Cu2+ (ag) + 2e Cu (s) Note: write the half reaction as it would actually occur at the cathode. 0.153 Cu2+ (aq) + e - Cu+ (aq) 0.521 Cu+ (aq) + e - Cu (s) 2.866 F2 (g) + 2e - 2F (aq) -0.447 Fe2+ (aq) + 2e-- Fe (s) Explanation Check 0.771 Fe+ (aq) + e- Fe2+ (aq) MacBook A FZ
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