V 0 A certain half-reaction has a standard reduction potential E +1.34 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that red must provide at least 1.20 V of electrical power The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. nh Data Is there a minimum standard reduction 0 E red Half-Reaction E (V) yes, there is a minimum. potential that the half-reaction used at the anode of this cell can have? 2F (aq) F2 (g) + 2e 2.866 If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Co3t (aq) + e Co2+ (aq) 1.92 no minimum -2H20 (I) H202 (aq) + 2Ht (aq) + 2e 1.776 Aut (aq) + e Au (s) 1.692 MnO4 (aq) + 8Ht (aq) + 5e Mn2 (aq) + 4H20 (I) 1.507 Is there a maximum standard reduction 0 E red Au3t (aq) +3e Au (s) 1.498 yes, there is a maximum. potential that the half-reaction used at the anode of this cell can have? Cl2 (g) + 2e 2Cl (aq) 1.35827 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. O2 (g) + 4H (aq) + 4e 2H20 (I) 1.229 no maximum Mn2+ (aq) + 2H20 (I) MnO2 (s) +4H+ (aq) + 2e 1.224 2103 (aq) 12H (aq) + 10e I2 (s) + 6H20 (I) 1.195 Br2 (I)2e 2Br (aq) 1.066 By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the anode of this cell. vo2+ (aq) + H2O (I) VO2+ (aq) 2H+ (aq) + e 0.991 HNO2 (aq) + H+ (aq) + e NO (g) + H20 (I) 0.983 N3 (aq) 4H+ (aq) + 3e- NO (g)+ 2H20 (I) 0.957 Note: write the half reaction as it would actually occur at the anode. Ag (aq) e Ag (s) 0.7996 Fe3+ (aq) + e Fe2+ (aq) 0.771 O2 (g) 2H(aq) + 2e H2O2 (aq) 0.695 Explanation Check MnO4 (aq) + 2H20 (I) 3e MnO2 (s) + 40H- (aq) 0.595
V 0 A certain half-reaction has a standard reduction potential E +1.34 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that red must provide at least 1.20 V of electrical power The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. nh Data Is there a minimum standard reduction 0 E red Half-Reaction E (V) yes, there is a minimum. potential that the half-reaction used at the anode of this cell can have? 2F (aq) F2 (g) + 2e 2.866 If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Co3t (aq) + e Co2+ (aq) 1.92 no minimum -2H20 (I) H202 (aq) + 2Ht (aq) + 2e 1.776 Aut (aq) + e Au (s) 1.692 MnO4 (aq) + 8Ht (aq) + 5e Mn2 (aq) + 4H20 (I) 1.507 Is there a maximum standard reduction 0 E red Au3t (aq) +3e Au (s) 1.498 yes, there is a maximum. potential that the half-reaction used at the anode of this cell can have? Cl2 (g) + 2e 2Cl (aq) 1.35827 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. O2 (g) + 4H (aq) + 4e 2H20 (I) 1.229 no maximum Mn2+ (aq) + 2H20 (I) MnO2 (s) +4H+ (aq) + 2e 1.224 2103 (aq) 12H (aq) + 10e I2 (s) + 6H20 (I) 1.195 Br2 (I)2e 2Br (aq) 1.066 By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the anode of this cell. vo2+ (aq) + H2O (I) VO2+ (aq) 2H+ (aq) + e 0.991 HNO2 (aq) + H+ (aq) + e NO (g) + H20 (I) 0.983 N3 (aq) 4H+ (aq) + 3e- NO (g)+ 2H20 (I) 0.957 Note: write the half reaction as it would actually occur at the anode. Ag (aq) e Ag (s) 0.7996 Fe3+ (aq) + e Fe2+ (aq) 0.771 O2 (g) 2H(aq) + 2e H2O2 (aq) 0.695 Explanation Check MnO4 (aq) + 2H20 (I) 3e MnO2 (s) + 40H- (aq) 0.595
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Corrosion is defined as an activity that transforms refined metals into more chemically stable forms such as oxide, hydroxide, carbonate, or sulfide. It refers to the slow decomposition of things (typically metals); thanks to chemical and/or electrochemical reactions with their surroundings. Corrosion engineering is the science of preventing and controlling corrosion.
Question
Is there a minimum or maximum standard reduction potential that the half-reaction can have. Then write the balanced equation
Transcribed Image Text:V
0
A certain half-reaction has a standard reduction potential E +1.34 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that
red
must provide at least 1.20 V of electrical power
The cell will operate under standard conditions.
Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell.
nh Data
Is there a minimum standard reduction
0
E
red
Half-Reaction
E (V)
yes, there is a minimum.
potential that the half-reaction used at
the anode of this cell can have?
2F (aq)
F2 (g) + 2e
2.866
If so, check the "yes" box and calculate
the minimum. Round your answer to 2
decimal places. If there is no lower
limit, check the "no" box.
Co3t (aq) + e
Co2+ (aq)
1.92
no minimum
-2H20 (I)
H202 (aq) + 2Ht (aq) + 2e
1.776
Aut (aq) + e
Au (s)
1.692
MnO4 (aq) + 8Ht (aq) + 5e
Mn2 (aq) + 4H20 (I)
1.507
Is there a maximum standard reduction
0
E
red
Au3t (aq) +3e
Au (s)
1.498
yes, there is a maximum.
potential that the half-reaction used at
the anode of this cell can have?
Cl2 (g) + 2e
2Cl (aq)
1.35827
If so, check the "yes" box and calculate
the maximum. Round your answer to 2
decimal places. If there is no upper
limit, check the "no" box.
O2 (g) + 4H (aq) + 4e
2H20 (I)
1.229
no maximum
Mn2+ (aq) + 2H20 (I)
MnO2 (s) +4H+ (aq) + 2e
1.224
2103 (aq) 12H (aq) + 10e
I2 (s) + 6H20 (I)
1.195
Br2 (I)2e 2Br (aq)
1.066
By using the information in the ALEKS
Data tab, write a balanced equation
describing a half reaction that could be
used at the anode of this cell.
vo2+ (aq) + H2O (I)
VO2+ (aq)
2H+ (aq) + e
0.991
HNO2 (aq) + H+ (aq) + e
NO (g) + H20 (I)
0.983
N3 (aq) 4H+ (aq) + 3e-
NO (g)+ 2H20 (I)
0.957
Note: write the half reaction as it would
actually occur at the anode.
Ag (aq) e Ag (s)
0.7996
Fe3+ (aq) + e
Fe2+ (aq)
0.771
O2 (g) 2H(aq) + 2e
H2O2 (aq)
0.695
Explanation
Check
MnO4 (aq) + 2H20 (I) 3e
MnO2 (s) + 40H- (aq)
0.595
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