Suppose you are given a 1M solution of SnCl2 and another 1M solution of MgCl2. Leaving the concentration of MgCl2 fixed, how many mL of 1M SnCl2 do you need to add to water to achieve a 50 mL solution of SnCl2 such that your new galvanic cell will read a voltage of 2.25V?Use the equation

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