Consider the following galvanic cells. Diagram I 14 1.0M Au³+ 1.0 M Cu 1.0 M Cu2+ gº Au- chemPad XX gº V (b) balanced cell equation II chemPad XX V For each galvanic cell, give the balanced cell reaction and determine 8. Standard reduction potentials are found in the Standard Reduction Potentials table. (Use the lowest possible whole number coefficients. Include states-of-matter under the given conditions in your answer.) (a) balanced cell equation I Help Greek Help Pt Greek Ⓡ Diagram II Cd- 1.0 M Cd2+ --Pt 1.0 M VO₂, 1.0 MH+ 1.0 M VO²+

Consider the following galvanic cells. Diagram I 14 1.0M Au³+ 1.0 M Cu 1.0 M Cu2+ gº Au- chemPad XX gº V (b) balanced cell equation II chemPad XX V For each galvanic cell, give the balanced cell reaction and determine 8. Standard reduction potentials are found in the Standard Reduction Potentials table. (Use the lowest possible whole number coefficients. Include states-of-matter under the given conditions in your answer.) (a) balanced cell equation I Help Greek Help Pt Greek Ⓡ Diagram II Cd- 1.0 M Cd2+ --Pt 1.0 M VO₂, 1.0 MH+ 1.0 M VO²+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential Br,(1)+2e - 2 Br (aq) =+1.065 V ʼred MnO,(aq)+2 H,O(1)+3e MnO,(s)+4 ОН (аq) E=+0.59 V (red Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. x10 Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written.
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A certain naif-reaction has a standard reduction potential Ed-0.53 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that must provide at least 0.80 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. Is there a minimum standard reduction potential that the half-reaction used at the anode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no tower limit, check the "no" box. Is there a maximum standard reduction potential that the half-reaction used at the anode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the…
Consider a galvanic electrochemical cell constructed using Cr/Cr³⁺ and Zn/Zn²⁺ at 25 °C. The following half-reactions are provided for each metal: Cr³⁺(aq) + 3 e⁻ → Cr(s) E°red = -0.744 V Zn²⁺(aq) + 2 e⁻ → Zn(s) E°red = -0.763 V Given that the standard cell potential is 0.019 V and the overall equation is 2 Cr³⁺ (aq) + 3 Zn (s) → 2 Cr (s) + 3 Zn²⁺ (aq), what is the cell potential for this cell at 25 °C when [Zn²⁺] = 0.0323 M and [Cr³⁺] = 0.1736 M?
MnO4– + Sn ----> MnO2 + Sn2+ A) Identify the half-reaction that occurs at the cathode. B) Identify the oxidizing agent and anode. C) standard cell potential? D) What will be the potential of a cell constructed using 57.0 g MnO2, 1.57 M MnO4–, 14.8 g Pt, 12.5 g Sn and 0.87 M Sn2+ at pH 2.5?
Consider the following voltaic cellat 25°C: Al(s) | Al3*(0.20 M, aq) || Al3+(0.75 M, aq) | Al(s) If the standard reduction potential for the Al3+(aq) /Al(s) redox couple is -1.66 V, what is the overall cell reaction and the cell potential of the voltaic cell shown above? (Reference the cell as written above.) The overall cell reaction is Al3+(0.75 M, aq) AIS*(0.20 M, ag) and E°cell = +0.0113 V. There is no overall cell reaction and E°cell = 0.00 V. The overall cell reaction is Al3+(0.20 M, aq) Als*(0.75 M, aq) and E°cell = +0.0113 V. The overall cell reaction is Al3+(0.20 M, aq) →A13+(0.75 M, ag) and E°cell| = -0.0113 V. The overall cell reaction is Al3*(0.75 M, aq) →AI3*(0.20 M, aq) and E°cell = -0.0113 V. None of these
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A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential 2+ Zn (aq)+2e - Zn(s) :-0.763 V (red |Cro (aq)+4 H2O(1)+3e Cr(OH)3(s)+5OH (aq) :-0.13 V = - (red Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. x10 Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written.
Using the standard reduction potentials here, calculate the standard potential for the following cell in V (make sure you don't round your answer): Culs)Cu2"(aq)||Mn2 (aq).H"(aq)|MnO2(s)Pt(s) Your Answer:
Consider the following galvanic cells. Diagram I Au- 1.0 M Au³+ chemPad XX 80 1.16 80 (b) balanced cell equation II chemPad X V For each galvanic cell, give the balanced cell reaction and determine &. Standard reduction potentials are found in the Standard Reduction Potentials table. (Use the lowest possible whole number coefficients. Include states-of-matter under the given conditions in your answer.) (a) balanced cell equation I 1.4 1.0 M Cu+ 1.0 M Cu²+ Au(s)+3Cu²+(aq) ⇒ Au³+(aq)+3Cu+(aq) |Au(s)+3Cu^2+(aq)Au^3+(aq)+3Cu^+(aq) Your answer indicates a reaction progressing in an inconsistent direction. -Pt Greek V i Diagram II Greek Cd- 1.0 M Cd2+ XX Enter a number. Cd(s)+2VO₂²+ (aq)+4H*(aq) ← Cd²+(aq)+2VO²+ (aq)+2H₂O(l) Cd(s)+2VO_2^2+(aq)+4H^+(aq)<--Cd^2+(aq)+2VO^2+(aq)+2H_2O(l) Your answer indicates a reaction progressing in an inconsistent direction. Help Help -Pt 1.0 M VO₂ 1.0 MH+ 1.0 M VO²+ i
Consider the half reactions in a cell: Pb2+ + 2 e ------ Pb(s) Eo = - 0.126 V Fe3+ + e ------ Fe2+ (aq) Eo = + 0.771 V Which of the following statement is correct for the cell? Given Given A. For a Galvanic cell the standard emf will be 0.645 V and Pb will be the anode B. For a Galvanic cell standard emf will be 0.645 V and Fe will be the cathode C. For a Galvanic cell standard emf will be 1.668 V and Pb will be cathode D. For a Voltaic cell the standard emf will be 0.897 V and Fe will be the anode E. For a Voltaic cell standard emf will be 0.897 V and Pb will be the anode