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What is the concentration of acetazolamide (B), in a 0.5000 M solution of acetazolamide (B)? What is the concentration of hydrogen acetazolamide (BH+) in a 0.5000 M solution of acetazolamide (B)?

What is the concentration of acetazolamide (B), in a 0.5000 M solution of acetazolamide (B)? What is the concentration of hydrogen acetazolamide (BH+) in a 0.5000 M solution of acetazolamide (B)?

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Acetazolamide is a carbonic anhydrase inhibitor that is used to treat glaucoma.  It has two acidic groups and has 2 pKb’s as shown below:

What is the concentration of acetazolamide (B), in a 0.5000 M solution of acetazolamide (B)?

What is the concentration of hydrogen acetazolamide (BH+) in a 0.5000 M solution of acetazolamide (B)?

This image depicts the stepwise protonation of a thiourea derivative. There are three chemical structures in a horizontal sequence, each connected by an equilibrium arrow. The equilibrium constants (K) are indicated above the arrows, showing the protonation steps. 1. **Left Structure (B)**: - Molecule: A thiourea derivative with a carbonyl group and an amino group attached to a five-membered ring containing nitrogen and sulfur atoms. - Label: (B) 2. **Middle Structure (BH⁺)**: - Molecule: Shows the protonation at the nitrogen atom, resulting in the addition of H⁺. - Equilibrium Constant: K1 = 6.31 x 10⁻⁸ - Label: (BH⁺) 3. **Right Structure (BH₂²⁺)**: - Molecule: Further protonation, adding another H⁺ to the molecule. - Equilibrium Constant: K2 = 1.00 x 10⁻⁹ - Label: (BH₂²⁺) This sequence illustrates the acidity constants associated with the protonation steps of the molecule. The K values indicate the equilibrium position of the protonation reactions, providing insight into the molecule's acid-base properties.
Transcribed Image Text:This image depicts the stepwise protonation of a thiourea derivative. There are three chemical structures in a horizontal sequence, each connected by an equilibrium arrow. The equilibrium constants (K) are indicated above the arrows, showing the protonation steps. 1. **Left Structure (B)**: - Molecule: A thiourea derivative with a carbonyl group and an amino group attached to a five-membered ring containing nitrogen and sulfur atoms. - Label: (B) 2. **Middle Structure (BH⁺)**: - Molecule: Shows the protonation at the nitrogen atom, resulting in the addition of H⁺. - Equilibrium Constant: K1 = 6.31 x 10⁻⁸ - Label: (BH⁺) 3. **Right Structure (BH₂²⁺)**: - Molecule: Further protonation, adding another H⁺ to the molecule. - Equilibrium Constant: K2 = 1.00 x 10⁻⁹ - Label: (BH₂²⁺) This sequence illustrates the acidity constants associated with the protonation steps of the molecule. The K values indicate the equilibrium position of the protonation reactions, providing insight into the molecule's acid-base properties.
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