We have a parallel plate capacitor with two plates containing charges + Q and -Q a distance d =0.108 m apart. We release a proton from rest at point A, just above the lower plate. At point B,just before the proton strikes the upper plate, the proton has a kinetic energy of 1x10 18J.Aproton has a charge of 1.602 x 10-19C. What is the magnitude of the electric field betweenthe plates (in V/m)?+QVAnswer: E(express your answers in tenths place or one decimal digit only)m

Given Distance d = 0.108 m Kinetic energy K.E = 1×10-18 J Proton charge q…

Answered: We have a parallel plate capacitor with…

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