The plates of a parallel-plate capacitor are 3.20 mm apart, and each has an area of 9.92 cm2 . Each plate carries a charge of magnitude 4.60×10−8 C . The plates are in vacuum. a) What is the capacitance? b) What is the potential difference between the plates? c) What is the magnitude of the electric field between the plates?
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The plates of a parallel-plate capacitor are 3.20 mm apart, and each has an area of 9.92 cm2 . Each plate carries a charge of magnitude 4.60×10−8 C . The plates are in vacuum.
a) What is the capacitance?
b) What is the potential difference between the plates?
c) What is the magnitude of the electric field between the plates?
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- Imagine a parallel plate capacitor with mica between the plates. Suppose the potential difference between the plates is 82V, and there is an electric field between the plates with a strength of 320 N/C. If each plate has an area of 0.030 square meters, a) What is the separation between the plates? b) Find the capacitance of the capacitor. c) How much charge is on each plate? d) How much energy is stored in the capacitor? For each part, explain your reasoning.A 0.079 μF capacitor is being held at a potential difference of 490 μV. a) What is the charge, in coulombs, on one of the plates? b) If you measure the size of each plate to be 49 cm2, how far apart are the plates, in micrometers? c) What is the magnitude of the electric field inside this capacitor, in newtons per coulomb?The separation distance between the two plates of a parallel plate capacitor is 2.47 cm. An electron is at rest near the negative plate. When it is released, it accelerates and reaches the positive plate with a kinetic energy of 6.30 10-15 J.What is the magnitude of the electric field in the region between the plates of the capacitor?
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