In the image given there are 3 charges along the y axis. it is your job to find an expression for electric potential at point P when : d
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electric potential at point P when : d <<r (or d/r << 1, but not zero. you can view the
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Solved in 4 steps with 1 images
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- I Review I Constants A 11.0 nC charge is at x = Ocm and a -1.3 nC charge is at x = 7 cm . Part A At what point or points on the x-axis is the electric potential zero? Express your answer using two significant figures. If there is more than one answer, give each answer separated by a comma. V ΑΣφ Xo = cm Submit Previous Answers Request AnswerLibrary CARES Drive to Video da Tutors utor J Context dShelf Digital A solid spherical conductor has a radius R and has a charge Q. Assume the potential is zero at infinity. Consider points inside the sphere, r < R, which of the following statements best describes the behavior of the electric potential, V,inside the sphere: O The electric potential is a non zero constant everywhere inside the sphere O The electric potential is zero everywhere inside the sphere, O The electric potential is proportional to the distance from the center Ohe electric potential is inversely proportional to the distance squared O The electric potential is inversely proportional to the distance cubed from the center 3126. E Two equipotential surfaces surround a +1.50 x 10-8 C point charge. How far is the 190-V surface from the 75.0-V surface? 27. E An equipotential surface that surrounds a point charge q has a potential of 490 V and an area of 1.1 m². Determine q.
- In the region shown in the image, there is a uniform electric field of magnitude 34.9 N/C which points in the negative x-direction. Points 2, 3, and 4 are all 0.245 m away from point 1, and the angle = 46.4°. Calculate the following potential differences V-V, where i and indicate the numbered points. V₂ - V₁ = V₁ - V₁ = V₁ - V₁ = V₁ - V₁ = V -02 XPart A A +4.0 µC charge is 22 cm to the right of a -7.8 µC charge. Determine the potential at the midpoint between the two charges. Express your answer to two significant figures and include the appropriate units. µẢ Vmid = Value Units Submit Request Answer Part B Determine the direction of the electric field at the midpoint between the two charges. O to the left. O to the right. Submit Previous Answers v Correct Part C Determine the magnitude of the electric field at the midpoint between the two charges. Express your answer to two significant figures and include the appropriate units. µA ? Emid = Value Unitsd and e
- A moving particle encounters an external electric field that decreases its kinetic energy from 9930 eV to 8130 eV as the particle moves from position A to position B. The electric potential at A is -59.0 V, and that at B is +13.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer. Number i Textbook and Medi Units Lower potential Higher potential VBThe figure below shows the equipotential surfaces of an electric dipole in the xy-plane. The x and y scales are in units of meter. The charge on the left is positive. Each color change represents a a change in the potential of 5 V. Estimate the magnitude and direction of the electric field in units of V/m N/C at x 13.5 m, y = 13.5 m. = 24.5 22.5 20.5 18.5 16.5 14.5 12.5 10.5 8.5 6.5 4.5 2.5 0.5 0.5 2.5 4.5 6.5 8.5 10.5 12.5 14.5 16.5 18.5 20.5 22.5 24.5A 5.60 μF parallel-plate air capacitor has a plate separation of 4.50 mm and is charged to a potential difference of 300 V. Part A Calculate the energy density in the region between the plates, in units of J/m³. Express your answer in joules per cubic meter. VE ΑΣΦ U = Submit Previous Answers Request Answer ? X Incorrect; Try Again; 2 attempts remaining J/m³
- 10. You need a coaxial cable that can hold ± 62 nC/m of charge density. Someone hands you a cable with a 2.0 mm diameter inner conductor and 1.6 cm outer conductor (see diagram at right). The maximum potential difference the cable will tolerate is 2 kV. Will this cable work for your application? a-Two particles with charges +2e and -5e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 5.51 x 10-10 m apart. What is EPE final - EPE initial, which is the change in the electric potential energy? Number i | UnitsTwo protons are maintained at a separation of 877 nm. Calculate the electric potential due to the two particles at the midpoint between them. Then, find the magnitude and direction of the electric field there. potential: magnitude of field: The direction of field is toward one of the protons. another direction. undetermined. V N/C