Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0cm. Each plate has a surface charge density of 50.0 nC/m2. A proton is released from rest at the positive plate. Given information: Kinetic energy of proton when it reaches the negative plate = 9.94*10^(-17)J Potential difference between plates = 621.19V Magnitude of the electric field between the plates from the charge density = 5.647kN/C a) Determine the speed of the proton just before it strikes the

Q: Oppositely charged parallel plates are separated by 4.50 mm. A potential difference of 600 V exists…

A: Potential difference between plate = V = 600v distance between plate = d = 4.5 mm = 4.5×10-3m

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Q: Two parallel plates having charges of equal magnitude but opposite sign are separated by 40.0 cm.…

A: Given, The distance between the plates: d=40 cm = 0.4 m The surface charge density of both the…

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A: Given,The electric field between the plates, E= 5.40×105 V/mIf the space between the space is filled…

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Q: A proton (mass = 1.67 x 10-27 kg, charge = 1.60 x 10-19 C) moves from point A to point B under the…

A: Velocity at point A =50 KM/S = 50000 k/s Velocity at point B =82.6 Km/ s = 82600 m/s Q( VA - VB) = W…

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A: Determine the number of protons and electrons in the box as follows.

Q: Two point charges lie along the x axis as shown in the figure below, where q1 = -5 µc and q2 = 1 µC.…

A: Given Q1 is -5 uC Q2 is 1 uC. r is .25m

Q: B В A 60 cm 30 cm !! 26 cm 26 сm Q1 =-50 µC Q2 = +50 µC 40 cm

A: Given : Q1 = -50μC = -50 * 10-6 C Q2 = 50μC = 50 * 10-6 C Distance between A and Q1 = 60 cm = 0.6 m…

Q: the objects mass is 70.0 kg and you initially put the boxes of protons and electrons 45 m apart. Now…

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Q: 1. In the figure particles 1 and 2 of charge q1 = q2 = +5.00 × 10-19 C are on a y axis at distance d…

A: Given data: Charge q1=q2=5×10-19C Distance d=18.00 cm=0.18m Charge q3=3.20×10-19C Distance x=28.00…

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Q: A small charged piece of Styrofoam is suspended between two large plates that produce a uniform…

A: Solution: As per the given data,   Here, The charge is negative since it has excess electrons.

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Q: Oppositely charged parallel plates are separated by 4.25 mm. A potential difference of 600 V exists…

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Q: Calculate the change in the kinetic energy Δ?,ΔK, potential energy Δ?,ΔU, and total energy Δ?ΔE of…

A: The change in charge’s kinetic energy can be given by work-energy theorem as, Here, K, W, F, Fe, E,…

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A: Given: The electric field is 360 Vm. The distance between the two plates is 30.0 cm. Introduction:…

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Q: Oppositely charged parallel plates are separated by 5.35 mm. A potential difference of 500 V exists…

A: Given: The separation between plates is 5.35 mm. The potential difference is 500 V.

Q: A proton is held at the positive plate parallel arrangement. The plates are 1.45 cm apart and the…

A: Given Separation between the plate is d=1.45 cm=0.0145 m Potential energy of the proton is…

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Q: Two particles of -10 nC each are arranged symmetrically on the x-axis. 15 cm 91 = -10 nC 10 cm y •P…

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Q: D1-RT60: UNIFORM ELECTRIC FIELD-POTENTIAL DIFFEREN Two parallel plates that have been charged create…

A: Given Data: The magnitude of uniform electric field E=30 NC Coordinates of point M (2,0) m…

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Q: Oppositely charged parallel plates are separated by 3.71 mm. A potential difference of 600 V exists…

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Q: Air "breaks down" when the electric field strength reaches 3××1066 N/CN/C, causing a spark. A…

A: *The given electric field is E = 3 × 106 N/C*The plate area is A = (4.5 cm × 4.5 cm)…