Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E = 5.40 x 105 V/m. When the space is filled with a dielectric, the electric field is E = 3.60 x 105 V/m. What is the charge density on each surface of the dielectric? (0 = 8.85 x 10 -12 F/m)

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Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the
electric field is E = 5.40 x 105 V/m. When the space is filled with a dielectric, the electric field is E = 3.60 x
105 V/m. What is the charge density on each surface of the dielectric? (so = 8.85 x 101 -12
F/m)
6.10 x 10-8 C/m²
3.19 x 10-6 C/m²
1.06 x 10-5 C/m²
2.03 x 10-8 C/m²
1.59 x 10-6 C/m².
4.07 x 10-8 C/m²
4.78 x 10-6 C/m²
Transcribed Image Text:Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E = 5.40 x 105 V/m. When the space is filled with a dielectric, the electric field is E = 3.60 x 105 V/m. What is the charge density on each surface of the dielectric? (so = 8.85 x 101 -12 F/m) 6.10 x 10-8 C/m² 3.19 x 10-6 C/m² 1.06 x 10-5 C/m² 2.03 x 10-8 C/m² 1.59 x 10-6 C/m². 4.07 x 10-8 C/m² 4.78 x 10-6 C/m²
Expert Solution
Step 1

Given,The electric field between the plates, E= 5.40×105 V/mIf the space between the space is filled with dielectric,the electric field between the plates, Ed = 3.60×105 V/mε0 = 8.85×10-12 F/m

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