Oppositely charged parallel plates are separated by 5.36 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field strength between the plates?  N/C (b) What is the magnitude of the force on an electron between the plates?  N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate?  J

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Oppositely charged parallel plates are separated by 5.36 mm. A potential difference of 600 V exists between the plates.

(a) What is the magnitude of the electric field strength between the plates?
 N/C
(b) What is the magnitude of the force on an electron between the plates?
 N
(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate?
 J
Expert Solution
Step 1

a)

Let the separation between the plates be d and the electric potential difference between the plates be V.

The magnitude of the electric field strength between the plates is calculated in the following way.

Advanced Physics homework question answer, step 1, image 1

 

 

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