Given two particles with Q = 2.90-μC charges as shown in the figure below and a particle with charge q = 1.32 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) į 0 Q x= -0.800 m x = 0.800 m X Q (a) What is the net force (in N) exerted by the two 2.90-µC charges on the charge q? (Enter the magnitude.) 0 ✓ N (b) What is the electric field (in N/C) at the origin due to the two 2.90-μC particles? (Enter the magnitude.) 0 ✔ N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.90-μC particles? 65.25 kV ✓ (d) What If? What would be the change in electric potential energy (in J) of the system if the charge were moved a distance d = 0.400 m closer to either of the 2.90-μC particles? 1.14*10**-13 X J

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter26: Electric Potential
Section: Chapter Questions
Problem 14PQ: Four charged particles are at rest at the corners of a square (Fig. P26.14). The net charges are q1...
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Given two particles with Q = 2.90-μC charges as shown in the figure below and a particle with charge q = 1.32 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞0.)
x = -0.800 m 0
x = 0.800 m
X
(a) What is the net force (in N) exerted by the two 2.90-μC charges on the charge q? (Enter the magnitude.)
0
✓
N
(b) What is the electric field (in N/C) at the origin due to the two 2.90-μC particles? (Enter the magnitude.)
0
✔ N/C
(c) What is the electrical potential (in kV) at the origin due to the two 2.90-μC particles?
65.25
✓ kV
(d) What If? What would be the change in electric potential energy (in J) of the system if the charge were moved a distance d = 0.400 m closer to either of the 2.90-μC particles?
1.14*10-13 X J
Transcribed Image Text:Given two particles with Q = 2.90-μC charges as shown in the figure below and a particle with charge q = 1.32 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞0.) x = -0.800 m 0 x = 0.800 m X (a) What is the net force (in N) exerted by the two 2.90-μC charges on the charge q? (Enter the magnitude.) 0 ✓ N (b) What is the electric field (in N/C) at the origin due to the two 2.90-μC particles? (Enter the magnitude.) 0 ✔ N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.90-μC particles? 65.25 ✓ kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge were moved a distance d = 0.400 m closer to either of the 2.90-μC particles? 1.14*10-13 X J
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