Four particles with the same charge q = 109 C are placed at the vertices of a square with side I = 12 cm. You need to calculate: a) the electric field in the center, O, of the square. b) the potential difference between O and the middle point, M, of the side of the square. c) the work that needs to be done to make the square smaller of side 1/2
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- Two parallel plates having charges of equal magnitude but opposite sign are separated by 10.0 cm. Each plate has a surface charge density of 48.0 nC/m2. A proton is released from rest at the positive plate. (a) Determine the magnitude of the electric field between the plates from the charge density. _____kN/C (b) Determine the potential difference between the plates. _____V (c) Determine the kinetic energy of the proton when it reaches the negative plate. _____J (d) Determine the speed of the proton just before it strikes the negative plate. _____km/s (e) Determine the acceleration of the proton. _____m/s2 towards the negative plate (f) Determine the force on the proton. _____N towards the negative plate (g) From the force, find the magnitude of the electric field. _____kN/C (h) How does your value of the electric field compare with that found in part (a)?A) Consider two metal plates separated by a dielectric material with a thickness of 4.5 cm. If the lower plate is at a potential of 9 V and the upper plate is at a potential of 0 V, what is the magnitude of the electric field generated between the plates? a) 200 V/m b) 40.5 V∙m c) 0.405 V∙cm d) 2 V/m B) What force will a proton feel in the uniform electric field from the question above? a) 32 N [towards upper plate] b) 3.2 x 10-17 N [towards upper plate] c) 6.48 x 10-18 N [towards lower plate] d) 64.8 N [towards lower plate]Three charges, QA=-4.1 µC, QB=5.0 µC, and Qc=2.9 µC are places on xy plane as shown in the picture below, with Qa placed at point (0, a), QB placed at (-a, -a) and Qc placed at (a, -a) . Determine the total electric potential at origin if a=3.4 m. y Q A а а a + Qc QB а Provide your answer in volts, rounded to the nearest integer.
- Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x = -51 cm and x = +51 cm. The charge densities on the planes are -42 nC/m2 and +23 nC/m2, respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x = +90 cm? (Hint: Use Gauss' law for planar symmetry to determine the electric field in each region of space.) Number i UnitsTwo widely separated charged metal spheres A and B have the same electrical surface potential. The ratio of the surfac charge densities of the two spheres is σA/OB = 7. The radius of sphere A is rA = 3 cm. What is the radius of sphere B 1) 0.42 cm (2) 0.18 cm (3) 21 cm (4) 147 cm (5) 3 crLet's consider a point charge Q = -4.53 nC in the x-y plane as shown in the figure. y (cm) 90 80 70 60 50 40 30 20 10 0 10 20 30 40 50 60 70 80 90 x (cm) What is the magnitude of the electric field at location P? What is the electric potential at location P?
- detailsA parallel-plate capacitor consists of two plates, each with an area of 25 cm2 separated by 3.0 mm . The charge on the capacitor is 4.8 nC . A proton is released from rest next to the positive plate. How long does it take for the proton to reach the negative plate? Express your answer with the appropriate units.Air "breaks down" when the electric field strength reaches 3××1066 N/CN/C, causing a spark. A parallel-plate capacitor is made from two 4.5 cmcm ×× 4.5 cmcm electrodes. How many electrons must be transferred from one electrode to the other to create a spark between the electrodes?
- Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.30×105 V/m. When the space is filled with dielectric, the electric field is E= 2.50×105 V/m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Energy density, both before and after the. What is the charge density on each surface of the dielectric? Express your answer in coulombs per meter squared. να ΑΣΦ ? |X| X•10" |oi| = C/m²An ionized nitrogen molecule (N₂+) at point A has charge +e and moves at 1.92 × 10³ m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop at point B, a distance of 0.796 mm past A on the > 2 axis. Calculate the x-component of the electric field and the potential difference between points A and B. (The mass of a nitrogen molecule is 4.65 x 107 kg and the fundamental charge is e = 1.60 × 10−¹9 C.) -26 HINT (a) the x-component of the electric field (in V/m) 672.96482 X V/m (b) the potential difference between points A and B (in V) VRegarding the Earth and a cloud layer 650 m above the Earth as the "plates" of a capacitor, calculate the capacitance if the cloud layer has an area of 1.53 km2. If an electric field of 2.0 × 106 N/C makes the air breakdown and conduct electricity (lightning), what is the maximum charge the cloud can hold? εo = 8.85 x 10−12 F/m