using namespace std; int main() [double degree [6] [2] =(30,40,10,70, 20, 30, 60, 70, 30, 10, 10, 85); int buffer=degree[0][0]; for (int i=1;i<6; i++) if (degree[i][0]>buffer) buffer=degree[i][0]; cout<

using namespace std; int main() [double degree [6] [2] =(30,40,10,70, 20, 30, 60, 70, 30, 10, 10, 85); int buffer=degree[0][0]; for (int i=1;i<6; i++) if (degree[i][0]>buffer) buffer=degree[i][0]; cout<

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <iostream> using namespace std; #define SIZE 5 //creating the queue using array int A[SIZE]; int front = -1; int rear = -1; //function to check if the queue is empty bool isempty() { if(front == -1 && rear == -1) return true; else return false; } //function to enter elements in queue void enqueue ( int value ) { //if queue is full if ((rear + 1)%SIZE == front) cout<<"Queue is full \n"; else { //now the first element is inserted if( front == -1) front = 0; //inserting element at rear end rear = (rear+1)%SIZE; A[rear] = value; } } //function to remove elements from queue void dequeue ( ) { if( isempty() ) cout<<"Queue is empty\n"; else //only one element if( front == rear ) front = rear = -1; else front = ( front + 1)%SIZE; } //function to show the element at front void showfront() { if( isempty()) cout<<"Queue is empty\n"; else cout<<"element at front is:"<<A[front]; } //function to display the queue void…
Exercise 1: Write a main program that reads the elements of a 2 x 2 integer matrix, A, from the user. It then performs the following tasks: • prints the matrix row-by-row using a nested looping structure, • adds all matrix elements in row 0 using a looping structure and prints the sum. For example, for matrix, A| [i 3 A[2][2] = 7 9 The Sample Session will be as follows: CA Microsoft Visual Studio Debug Console Enter element at row 0 column 0: 1 Enter element at row e column 1: 3 Enter element at row 1 column 0: 7 Enter element at row 1 column 1: 9 The matrix entered by the user is: 13 7 9 Sum of row 0 elements: 4 C:\Users\User\source\repos \Project1\Debug\Project1.exe (process 52912) exited with code 0. Press any key to close this window
#include <stdio.h> #include <string.h> int IsPasswordOkay(char* pass) { char Password[12]; strcpy(Password, pass); if (!strcmp(Password, "goodpass")) return(1); else return(0); } int main(int argc, char **argv) { int PwStatus; if (argc < 2) { printf("Input your password\n"); return(-1); } PwStatus = IsPasswordOkay(argv[1]); if (PwStatus == 0) { printf("Acces denied"); return(-1); } else { printf("Access granted"); return(1); } } Write a function to conduct input validation to secure the smallest buffer. You may call this function void SecurePasswordBuffer(const char *arg).
import java.lang.System; 3. public class FibonacciComparison { 4. // Fibonacci Sequence: 0, 1, 1, 2, 3, 5, 8 .... /* 7 input cases 8. 1) 0 9 2) 3 10 3) -1 11 4) 9 12 output cases 13 1) 0 14 2) 2 15 3) 0 16 4) 34 17 */ // Note that you need to return 0 if the input is negative. // Please pay close attention to the fact that the first index in our fib sequence is 0. 18 19 20 // Recursive Fibonacci public static int fib(int n) { // Code this func. 21 22 23 24 return -1; 25 26 // Iterative Fibonacci 27 28 public static int fiblinear(int n) { // Code this func. 29 30 return -1; 31 32 33 public static void main(String[] args) { 34 // list of fibonacci sequence numbers int[] nlist w { 5,10, 15, 20, 25, 30, 35, 40, 45}; 35 36 37 // Two arrays (one for fibLinear, other for fibRecursive) to store time for each run. // There are a total of nlist.length inputs that we will test double[] timingsEF = new double[nlist.Length]; double[] timingsLF = new double[nlist.length]; 38 39 40 41 42 // Every…
def dotProduct(Vs): V1 #get first vector from Vs ......... V2 #get second vector from Vs #check if they are in the same length ......... if ......... ...... ... #complete as needed ......... for in ...... ... ......... . dp #dp: dot-product ......... #complete as needed #u = (-2 4 -2) and v = (-3 6 3) u = . .; #setup u an v as a numpy array V Vc = [. ., #test the function using u and v print (.) #print "Dot-product of vectors is
Use iterators to print each element of v separted by spaces. #include <iostream>#include <vector> using namespace std; int main(){vector<int> v = {1, 3, 5}; (.....) }
A function in C++ that takes input from the user and stores it in an array #include<iostream> using namespace std; int main(int argc, char const *argv[]){int size = 5;int arr[size]; return 0; }
given code lab4 #include <stdio.h>#include <stdlib.h> /* typical C boolean set-up */#define TRUE 1#define FALSE 0 typedef struct StackStruct{int* darr; /* pointer to dynamic array */int size; /* amount of space allocated */int inUse; /* top of stack indicator - counts how many values are on the stack */} Stack; void init (Stack* s){s->size = 2;s->darr = (int*) malloc ( sizeof (int) * s->size );s->inUse = 0;} void push (Stack* s, int val){/* QUESTION 7 *//* check if enough space currently on stack and grow if needed */ /* add val onto stack */s->darr[s->inUse] = val;s->inUse = s->inUse + 1;} int isEmpty (Stack* s){if ( s->inUse == 0)return TRUE;elsereturn FALSE;} int top (Stack* s){return ( s->darr[s->inUse-1] );} /* QUESTION 9.1 */void pop (Stack* s){if (isEmpty(s) == FALSE)s->inUse = s->inUse - 1;} void reset (Stack* s){/* Question 10: how to make the stack empty? */ } int main (int argc, char** argv){Stack st1; init (&st1);…
Convert to C language #include <bits/stdc++.h>using namespace std; //hash function 1int main(){ string s; cout << "enter number\n"; cin >> s; //f(s)=no of digit in s=length of s cout << s << "->" << s.length(); return 0;} Output:
C++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the main code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; int length; string str; char top; bool flag = true; cin >> test; switch (test) { case 0: getline(cin, str); length = str.length(); for(int i = 0; i < length; i++){ if(str[i] == '{' || str[i] == '(' || str[i] == '['){ stack->push(str[i]); } else if (str[i] == '}' || str[i] == ')' || str[i] == ']'){ if(!stack->isEmpty()){ top = stack->top(); if(top == '{' && str[i] == '}' || top == '(' && str[i] == ')' ||…
C++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow #include "stack.h" #include "linkedlist.h" // SLLStack means Singly Linked List (SLL) Stack class SLLStack : public Stack { LinkedList* list; public: SLLStack() { list = new LinkedList(); } void push(char e) { list->add(e); return; } char pop() { char elem; elem = list->removeTail(); return elem; } char top() { char elem; elem = list->get(size()); return elem; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } };
#include #include using namespace std; void PrintSize(vector numsList) { cout intList (3); PrintSize(intList); cin >> currval; while (currval >= 0) { } Type the program's output intList.push_back(currval); cin >> currVal; PrintSize(intList); intList.clear(); PrintSize(intList); return 0; 1 se mice with camScanner Check Next Input 1234-1 Output