This program doesn't terminate when it's run:#include "csapp.h"int main() {}int fdsA[2];int fdsB[2];char buffer [2];pid_t pid;Pipe (fdsA);Pipe(fdsB);pid= Fork();if (pid == 0) {}Dup2(fdsA[0], 0);Dup2 (fdsB[1], 1);printf("hi");fgets (buffer, 2, stdin);return 0;Read(fdsB[0], buffer, 1);Write(fdsA[1], "ok", 2);Why?Waitpid(pid, NULL, 0);return 0;fgets(buffer, 2, stdin) reads only one byte from stdin,so it needs to read the second byte to terminatefile descriptors are not closed as they should beO the parent and child processes both try to write to'buffer"hi" printed by the child process is buffered andnever delivered to a pipe

The given program doesn't terminate after running. We will check why it is terminated. The…

Answered: This program doesn't terminate when…

This program doesn't terminate when it's run: #include "csapp.h" int main() { int fdsA[2]; int fdsB[2]; char buffer [2]; pid_t pid; Pipe (fdsA); Pipe(fdsB); pid Fork();

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

This program doesn't terminate when it's run:
#include "csapp.h"
int main() {
}
int fdsA[2];
int fdsB[2];
char buffer [2];
pid_t pid;
Pipe (fdsA);
Pipe(fdsB);
pid= Fork();
if (pid == 0) {
}
Dup2(fdsA[0], 0);
Dup2 (fdsB[1], 1);
printf("hi");
fgets (buffer, 2, stdin);
return 0;
Read(fdsB[0], buffer, 1);
Write(fdsA[1], "ok", 2);
Why?
Waitpid(pid, NULL, 0);
return 0;
fgets(buffer, 2, stdin) reads only one byte from stdin,
so it needs to read the second byte to terminate
file descriptors are not closed as they should be
O the parent and child processes both try to write to
'buffer
"hi" printed by the child process is buffered and
never delivered to a pipe

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