void fun(int i){do{if (i % 2 != 0)cout <=1);cout << endl;}int main(){int i = 1;while (i <= 8){fun(i);it;}cout <

Here C++ Code is given, output for the code is given below.

Answered: void fun(int i) { do { if (i % 2 != 0)…

Engineering

Computer Science

void fun(int i) { do { if (i % 2 != 0) cout <= 1); 1. cout << endl; } int main() { int i= 1;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

C programming #include <stdio.h>int main() {int i, j, n ;printf("height? ") ;scanf("%2d", &n) ;for (i = 1 ; i <= n ; i++) {// printf("%d: ", i) ;for (j = 1 ; j <= i ; j++) {// Pick *one* of the following// printf("%d", j % 10) ;printf("*") ;}printf("\n") ;}return 0 ;} How can I get output like this by editing the given programming -- height? 5************************* and then how can I get the following?- height? 7 1 123 12345 1234567 123456789 12345678901 1234567890123
int machineCompare1(struct machine* mac1, struct machine* mac2){ struct mac1; struct mac2; char make1[21], make2[21]; char model1[51], model2[21]; if((lap1 -> make1 == lap2 -> make2) && (lap1 -> model1 == lap2 -> model2)) return 0; else return 1;} have to create function to compare make and model of 2 machines - it's using structures - not sure if this is correct/ on the right track?
//Test isEqual function cout << endl << "Testing isEqual function"; cout << endl << "------------------------" << endl; if (isEqual(s2, s3)) cout << "s2=\"" << s2 << "\" and s3=\"" << s3 << "\" are equal" << endl; else cout << "s2=\"" << s2 << "\" and s3=\"" << s3 << "\" are not equal" << endl; delete[] s3; s3 = getCopy(s2); if (isEqual(s2, s3)) cout << "s2=\"" << s2 << "\" and s3=\"" << s3 << "\" are equal" << endl; else cout << "s2=\"" << s2 << "\" and s3=\"" << s3 << "\" are not equal" << endl; bool isEqual(const charPtr s1, const charPtr s2){/*returns true if the cstring s1 is equal to the cstring s2Definition: Two c-strings s1 and s2 are equal if they have the same lengthand characters of s1 and s2 at corresponding indexes are the same.*/ }
C++ Program #include <iostream>#include <cstdlib>#include <ctime>using namespace std; int getData() { return (rand() % 100);} class Node {public: int data; Node* next;}; class LinkedList{public: LinkedList() { // constructor head = NULL; } ~LinkedList() {}; // destructor void addNode(int val); void addNodeSorted(int val); void displayWithCount(); int size(); void deleteAllNodes(); bool exists(int val);private: Node* head;}; // function to check data exist in a listbool LinkedList::exists(int val){ if (head == NULL) { return false; } else { Node* temp = head; while (temp != NULL) { if(temp->data == val){ return true; } temp = temp->next; } } return false;} // function to delete all data in a listvoid LinkedList::deleteAllNodes(){ if (head == NULL) { cout << "List is empty, No need to delete…
in c++ i have this struct struct Student { string firstName, lastName; int pointTotal; }; void printStudent(const Student & s) { cout << s.pointTotal << "\t" << s.lastName << ", " << s.firstName << endl;}void printAll(Student students[], int numStudents) { for (int i = 0; i < numStudents; i++) printStudent(students[i]); cout << endl;}int main() { const int NUMSTUDENTS = 7; Student students[NUMSTUDENTS] = { {"Brian", "Jones", 45},{"Edith", "Piaf", 45},{"Jacques", "Brel", 64},{"Anna", "Brel", 64}, {"Carmen", "Jones", 45} , {"Carmen", "Brel", 64}, {"Antoine", "Piaf", 45}, {"Pascal", "Piaf", 64} }; printAll(students, NUMSTUDENTS); sortByPointTotal(students, NUMSTUDENTS); printAll(students, NUMSTUDENTS); return 0;} i need to make a function that uses bubble sort(coded from scratch), but modify it so that the comparison for out-of-order elements takes into account all three fields:…
Define a header file named BST.h. In this header file, declare your BST class./*** header file BST.h*/class BST {private:struct TreeNode {int val;TreeNode* left;TreeNode* right;};TreeNode* root;// private function declarations here....public:// public function declarations here...} (C++)
#include <iostream>using namespace std;class st{private:int arr[100];int top;public:st(){top=-1;}void push(int ItEM) {top++;arr[top]=ItEM; }bool ise() {return top<0;} int pop(){int Pop;if (ise()) cout<<"Stack is emptye ";else{Pop=arr[top];top--;return Pop;}}int Top(){int TOP;if (ise()) cout<<" empty ";else {TOP=arr[top];return TOP;}}void screen(){ for (int i = 0; i <top+1 ; ++i) {cout<<arr[i];} }};int main() {st c;c.push(1);c.push(2);c.push(3);c.push(4);c.pop();c.push(5);c.screen();return 0;} alternative to this code??
>> IN C PROGRAMMING LANGUAGE ONLY << COPY OF DEFAULT CODE, ADD SOLUTION INTO CODE IN C #include <stdio.h>#include <stdlib.h>#include <string.h> #include "GVDie.h" int RollSpecificNumber(GVDie die, int num, int goal) {/* Type your code here. */} int main() {GVDie die = InitGVDie(); // Create a GVDie variabledie = SetSeed(15, die); // Set the GVDie variable with seed value 15int num;int goal;int rolls; scanf("%d", &num);scanf("%d", &goal);rolls = RollSpecificNumber(die, num, goal); // Should return the number of rolls to reach total.printf("It took %d rolls to get a \"%d\" %d times.\n", rolls, num, goal); return 0;}
C++ complete magic Square #include <iostream> using namespace std; /*int f( int x, int y, int* p, int* q ){if ( y == 0 ){p = 0, q = 0;return 404; // status: Error 404}*p = x * y; // product*q = x / y; // quotient return 200; // status: OK 200} int main(){int p, q;int status = f(10, 2, &p, &q);if ( status == 404 ){cout << "[ERR] / by zero!" << endl;return 0;}cout << p << endl;cout << q << endl; return 0;}*/ /*struct F_Return{int p;int q;int status;}; F_Return f( int x, int y ){F_Return r;if ( y == 0 ){r.p = 0, r.q = 0;r.status = 404;return r;}r.p = x * y;r.q = x / y;r.status = 200;return r;} int main(){F_Return r = f(10, 0);if ( r.status == 404 ){cout << "[ERR] / by zero" << endl;return 0;}cout << r.p << endl;cout << r.q << endl;return 0;}*/ int sumByRow(int *m, int nrow, int ncol, int row){ int total = 0;for ( int j = 0; j < ncol; j++ ){total += m[row * ncol + j]; //m[row][j];}return total; } /*…
Consider the following C++ code segment: int d = 20; int f(int b) { static int c = 0; c *= b; return c; } int main() { int a; cin >> a; cout << f(a) * d << endl; }For each variable a, b, c, d: identify all type bindings and storage bindings for each binding, determine when the binding occurs identify the scope and lifetime
Determine all the output from the following program as it would appear on the screen. void func1(int); void func2(int = 4, int = 5, int = 2); int func3(int &, int, int); %3D int main() { int x = 0, z = 0, y = 2; func1(y); cout << y << endl; func2(x, y, z); func2(); func3(x, y, z); = Z func1(x); cout << x << " " << y << " " << z << endl; return 0; } void func1(int b) { static int a;
Please explain this question void main() {int a =300; char *ptr = (char*) &a ; ptr ++; *ptr =2; printf("%d", a); }