73%void showLinked()Linked_List "p;p=List;while(pl=NULL){cout<name< age<phoneN0<ID_NO<next;cout<>k;for(int i=0;i>nam;couts<"Enter student Age : ";cin>>ag:cout<<" Enter student PH NO:";cin>>ph:couts<"Enter student ID NO : ":cin>>id;InserFront(nam,ag.ph,id);couts<".--"<d;for (int i=0;i

#include <bits/stdc++.h> using namespace std; class Node { public: int data; Node *next;…

void showLinked() Linked_List "p; p=List; while(pl-NULL) cout<name age<phoneNO<ID_NOnext; } cout<>k; for(int l=0;1>nam; couts<"Enter student Age : "; cin>>ag; couts<" Enter student PH NO : "; cin>>ph; couts<"Enter student ID NO : "; cin>>id; InserFront(nam,ag.ph,id); couts<"- -"<d; for (int i=0;i

void showLinked() Linked_List "p; p=List; while(pl-NULL) cout<name age<phoneNO<ID_NOnext; } cout<>k; for(int l=0;1>nam; couts<"Enter student Age : "; cin>>ag; couts<" Enter student PH NO : "; cin>>ph; couts<"Enter student ID NO : "; cin>>id; InserFront(nam,ag.ph,id); couts<"- -"<d; for (int i=0;i

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Provide a detailed explanation line by line. Explain how this C++ program functionsSource Codes #include <iostream> using namespace std; // Node struct to hold data and pointer to next node struct Node { int data; Node* next; }; // Linked List class class LinkedList { private: Node* head; // pointer to head node public: LinkedList() { head = NULL; // initialize head to NULL } // Insert a new node at the front of the list void insert(int value) { Node* newNode = new Node(); // create a new node newNode->data = value; // set the data of the new node to the input value newNode->next = head; // set the next pointer of the new node to the current head node head = newNode; // set the head pointer to the new node } // Delete a node with a specific value from the list void deleteNode(int value) { Node* current = head; // set a pointer to the current node Node* previous =…
Given the following C code: struct Node int data: struct Node* prev: struct Node next: Which one of following statements delete the node pointed by X? (Assume that X does not point to head or tail of the linked list) a) X->prev->next-x->prev; X->next->prev-X->next: b) X->prev->prev-X->next; c) X->prev->next-X->next: d) X->prev->prev-X->prev: X->next->next-X->prev: X->next->prev-X->prev; X->next->next-X->next:
Assume that nodeType struct was defined as below. struct nodeType { int info; nodeType *link; }; And nodeType *n, *F, *L, *p, *q; Given initially the following linked list and new node n. n F р ‚-o-do-d F What are the steps to be executed to get the following linked list? O n->link=nullptr; p->link=n; L=n; On->link=nullptr; L->link=n; L=n; On=L; -ooooo n->link=nullptr; O L=n; n->link=nullptr; L->link=n; O L=n; ? L->link=n; n->link=nullptr; O n->link=nullptr; n=L; هم O It is not possible р n L
O problem 12 Language/Type: Related Links: Author: Java ListNodes LinkedLists LinkedIntList.java Marty Stepp Write the code necessary to convert the following sequence of ListNode objects: list -> [5] -> [4] -> [3] / Into this sequence of ListNode objects: list [4] -> [5] -> [3] / Assume that you are using ListNode class as defined in lecture and section: public class ListNode { public int data; // data stored in this node public ListNode next; // a link to the next node in the list } public ListNode () { ode() {...} public ListNode(int data) { ... } public ListNode(int data, ListNode next) { ... }
struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
In OCaml Programming Language, write a function: val prime_separator : int list -> int list * int list = <fun> that takes an integer list as an input, and returns a pair of integer lists where the prime numbers are in the first while the composite numbers are in the second returned list. #prime_separator [1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11];; - : int list * int list = ([11; 7; 5; 3; 2], [10; 9; 8; 6; 4; 1])
C++ DOUBLY LINKED LIST: Implement the remove_between function for my code: Incomplete code: #include <cstdlib>#include <iostream>using namespace std; class DoublyLinkedList : public List { node* head; node* tail; int index; node* create_node(int num, node* predecessor, node* successor) { node* n = (node*) malloc( sizeof(node) ); n->element = num; n->next = successor; n->prev = predecessor; return n; } void add_between(int num, node* predecessor, node* successor) { node* newest = create_node(num, predecessor, successor); predecessor->next = newest; successor->prev = newest; index++; } void remove_between(int num, node* predecessor, node* successor) { ///// CODE HERE }
Please discribe
#include <iostream> usingnamespace std; class Queue { int size; int* queue; public: Queue(){ size = 0; queue = new int[100]; } void add(int data){ queue[size]= data; size++; } void remove(){ if(size ==0){ cout <<"Queue is empty"<<endl; return; } else{ for(int i =0; i < size -1; i++){ queue[i]= queue[i +1]; } size--; } } void print(){ if(size ==0){ cout <<"Queue is empty"<<endl; return; } for(int i =0; i < size; i++){ cout<<queue[i]<<" <- "; } cout << endl; } //your code goes here }; int main(){ Queue q1; q1.add(42); q1.add(2); q1.add(8); q1.add(1); Queue q2; q2.add(3); q2.add(66); q2.add(128); q2.add(5); Queue q3 = q1+q2; q3.print();…
EXCEPTION: A linked list cannot represent a set. This is a set data structure without values. Sets have no duplicates. Sets are amenable to mathematical set functions like union and intersection.
// FILL IN THE BLANKS (LINKED-LISTS CODE) (C++)#include<iostream>using namespace std; struct ________ {int data ;struct node *next; }; node *head = ________;node *createNode() { // allocate a memorynode __________;temp = new node ;return _______ ;} void insertNode(){node *temp, *traverse;int n;cout<< "Enter -1 to end "<<endl;cout<< "Enter the values to be added in list"<<endl;cin>>n; while(n!=-1){temp = createNode(); // allocate memorytemp->data = ________;temp->next = ________;if ( ___________ == NULL){head = _________;} else {traverse = ( );while (traverse->next != ________{traverse = traverse-> ___________;} traverse->next= temp;} cout<<"Enter the value to be added in the list"<<endl;cin>>n; }} void printlist(){node *traverse = head; // if head == NULLwhile (traverse != NULL) { cout<<traverse->data<<" ";traverse = traverse->next;}} int main(){int option; do{cout<<"\n =============== MAIN…
Create a user-defined function called duplicates. This function will check to see if a singly linked list contains nodes with the same data stored. If any duplicates are found, return the value 1. Otherwise return 0. You may use the following typedef structure. typedef struct node_s{ int data; struct node_s * nextptr; }node_t;