3 9 12 15 ListB з | 4 1 2 Based on above memory illustrations. Complete these following fragment code : (i), (ii), (iii) Hint : Array ListB is the manipulation of array ListA. int ListA[5] = // (i) initialization of array ListA int ListB[5]; for( int i = 0; ; i++){ //(ii) control expression for maximum index ListB[i] = ;//(ii) manipulate elements in ListA to save in ListB cost < [> }
3 9 12 15 ListB з | 4 1 2 Based on above memory illustrations. Complete these following fragment code : (i), (ii), (iii) Hint : Array ListB is the manipulation of array ListA. int ListA[5] = // (i) initialization of array ListA int ListB[5]; for( int i = 0; ; i++){ //(ii) control expression for maximum index ListB[i] = ;//(ii) manipulate elements in ListA to save in ListB cost < [> }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
![3
6.
9
12
15
ListB
1
2
3
Based on above memory illustrations. Complete these following fragment code: (i), (ii), (iii)
Hint : Array ListB is the manipulation of array ListA.
int ListA[5] =
// (i) initialization of array ListA
int ListB[5];
for( int i = 0;
i++){ //(ii) control expression for maximum index
ListB[i] =
;//(ii) manipulate elements
ListA to save in ListB
cost < [>
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e1d65d1-b5b6-4665-bc1e-e01dfde811bd%2F47678929-3886-49bd-932c-5f30ec82026f%2Frcqxcsq_processed.png&w=3840&q=75)
Transcribed Image Text:3
6.
9
12
15
ListB
1
2
3
Based on above memory illustrations. Complete these following fragment code: (i), (ii), (iii)
Hint : Array ListB is the manipulation of array ListA.
int ListA[5] =
// (i) initialization of array ListA
int ListB[5];
for( int i = 0;
i++){ //(ii) control expression for maximum index
ListB[i] =
;//(ii) manipulate elements
ListA to save in ListB
cost < [>
}
![A.
(i) [ 3,6,9,12,15];
(ii) i< =4;
(iii) ListA [i] /3;
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA / 3;
C.
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA [i] /3;
D.
(i) { 3,6,9,12,15}
(ii) i < 5;
(iii) ListB /3;
B.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e1d65d1-b5b6-4665-bc1e-e01dfde811bd%2F47678929-3886-49bd-932c-5f30ec82026f%2F5ff3rrv_processed.png&w=3840&q=75)
Transcribed Image Text:A.
(i) [ 3,6,9,12,15];
(ii) i< =4;
(iii) ListA [i] /3;
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA / 3;
C.
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA [i] /3;
D.
(i) { 3,6,9,12,15}
(ii) i < 5;
(iii) ListB /3;
B.
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