Answered: Using Documented Problem Solutions ,…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Using Documented Problem Solutions , calculate the volume of each product and the energy involved for the complete combustion of 1,825.0 mL of propane (C3H8) gas and 8.00L of oxygen gas at 760.0 mmHg and 25.00C.Use conversion for ideal gas law units with the significant figures from Ebbing text. show all your work!

I know the balanced equation is C3H8+5O2-->3CO2+4H20

Propane = n= (1.000atm)(1.825L)

--------------------------

(0.08206 l atm/mol k)(298K)

Oxygen Gas = n= (1.000atm)(8.00L)

---------------------- = 0.3271464487

(0.08206 l atm/mol k)(298K)

C3H8+5O2-->3CO2+4H20

(-103.9)(0)+(3)(-393.5)+(4)(-285.8)=-2202 kJ

C3Hq + 50g 3 CO+ 4 Hg0
AS'
AG° =
LR amount
combustion aCmannt
रटी)

Definition Definition Law that is the combined form of Boyle's Law, Charles's Law, and Avogadro's Law. This law is obeyed by all ideal gas. Boyle's Law states that pressure is inversely proportional to volume. Charles's Law states that volume is in direct relation to temperature. Avogadro's Law shows that volume is in direct relation to the number of moles in the gas. The mathematical equation for the ideal gas law equation has been formulated by taking all the equations into account: PV=nRT Where P = pressure of the ideal gas V = volume of the ideal gas n = amount of ideal gas measured in moles R = universal gas constant and its value is 8.314 J.K-1mol-1 T = temperature

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