Part ACalculate the enthalpy change for the reactionP4O6 (s) + 202(g) → PĄO10 (s)given the following enthalpies of reaction:P4(s) +302(g) → P4O6 (s),PA(s) + 502(g) →PĄO10 (s),ΔΗ= -1640.1 kJΔΗ-2940.1 kJExpress your answer in kilojoules to four significant figures.ΑΣφ- 1300.1%3D-kJSubmitPrevious Answers Request AnswerX Incorrect; Try Again; One attempt remainingHess's law states that, if a reaction is carried out in a series of steps, AH for the overall reaction equals the sum of the enthalpy changes for the individual steps.Manipulate the reactions with the known enthalpies so that the reactants and products of the overall reaction appear on the appropriate sides of each equation and in thesame quantity. Then use the enthalpy of each step to calculate the enthalpy of the overall reaction.First launch this video. During the video, you'll see an example of a similar problem. After watching the video, try the question again. You can watch the video again at anypoint.Provide FeedbackNext >P PearsonCopyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy Permissions | Contact Us |MacBook Pro com/course.html?courseld%=16522083&OpenVellumHMAC=5d656202e951e64e7035fe2c56b6cb03#10302Review - I Constants I Periodic TablePart ACalculate the enthalpy change for the reactionP,O6 (s) + 202 (g) → PĄO10 (s)given the following enthalpies of reaction:P4(s) + 302(g) –→PĄO6(s),P4(s) + 502(g) → PĄO10 (s),ΔΗ-1640.1 kJ%3DΔΗ-2940.1 kJExpress your answer in kilojoules to four significant figures.ΑΣφ+1640.1%3DrxnkJSubmitPrevious Answers Request AnswerX Incorrect; Try Again; 3 attempts remainingProvide FeedbackNext >P PearsonCopyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |MacBook Pro

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Part A Calculate the enthalpy change for the reaction P,O6 (s) + 202(g)→P,010 (s) given the following enthalpies of reaction: P:(s) + 302(g) → P,O6 (s), P:(s) + 502(g) → P.O10 (s), ΔΗ -1640.1 kJ ΔΗ -2940.1 kJ Express your answer in kilojoules to four significant figures. AHm = 1300.1 kJ Submit Previous Answers Request Answer

Part A Calculate the enthalpy change for the reaction P,O6 (s) + 202(g)→P,010 (s) given the following enthalpies of reaction: P:(s) + 302(g) → P,O6 (s), P:(s) + 502(g) → P.O10 (s), ΔΗ -1640.1 kJ ΔΗ -2940.1 kJ Express your answer in kilojoules to four significant figures. AHm = 1300.1 kJ Submit Previous Answers Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

Part A
Calculate the enthalpy change for the reaction
P4O6 (s) + 202(g) → PĄO10 (s)
given the following enthalpies of reaction:
P4(s) +302(g) → P4O6 (s),
PA(s) + 502(g) →PĄO10 (s),
ΔΗ
= -1640.1 kJ
ΔΗ
-2940.1 kJ
Express your answer in kilojoules to four significant figures.
ΑΣφ
- 1300.1
%3D
-
kJ
Submit
Previous Answers Request Answer
X Incorrect; Try Again; One attempt remaining
Hess's law states that, if a reaction is carried out in a series of steps, AH for the overall reaction equals the sum of the enthalpy changes for the individual steps.
Manipulate the reactions with the known enthalpies so that the reactants and products of the overall reaction appear on the appropriate sides of each equation and in the
same quantity. Then use the enthalpy of each step to calculate the enthalpy of the overall reaction.
First launch this video. During the video, you'll see an example of a similar problem. After watching the video, try the question again. You can watch the video again at any
point.
Provide Feedback
Next >
P Pearson
Copyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy Permissions | Contact Us |
MacBook Pro

com/course.html?courseld%=16522083&OpenVellumHMAC=5d656202e951e64e7035fe2c56b6cb03#10302
Review - I Constants I Periodic Table
Part A
Calculate the enthalpy change for the reaction
P,O6 (s) + 202 (g) → PĄO10 (s)
given the following enthalpies of reaction:
P4(s) + 302(g) –→PĄO6(s),
P4(s) + 502(g) → PĄO10 (s),
ΔΗ
-1640.1 kJ
%3D
ΔΗ
-2940.1 kJ
Express your answer in kilojoules to four significant figures.
ΑΣφ
+1640.1
%3D
rxn
kJ
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 3 attempts remaining
Provide Feedback
Next >
P Pearson
Copyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |
MacBook Pro

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