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Calculate enthalpy of reaction given reaction enthalpies for proposed steps in a process. K+(g) + Cl-(g) → KCI(s) KCI (LE) = ? Cl2(g) → 2CI(g) Cl-CI (BE) = 243 kJ/mol %3D K(g) → K+(g) + 1e- K (IE) = 419 kJ/mol K(s) → K(g) K (AHsub) = 89.0 kJ/mol %3D Cl(g) + 1e- > Cl-(g) CI (EA) = -349 kJ/mol K(s) + 1/2C12(g) > KCI(s) KCI (AH;) = -436.5 kJ/mol

Calculate enthalpy of reaction given reaction enthalpies for proposed steps in a process. K+(g) + Cl-(g) → KCI(s) KCI (LE) = ? Cl2(g) → 2CI(g) Cl-CI (BE) = 243 kJ/mol %3D K(g) → K+(g) + 1e- K (IE) = 419 kJ/mol K(s) → K(g) K (AHsub) = 89.0 kJ/mol %3D Cl(g) + 1e- > Cl-(g) CI (EA) = -349 kJ/mol K(s) + 1/2C12(g) > KCI(s) KCI (AH;) = -436.5 kJ/mol

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.7: Enthalpy Calculations
Problem 1RC
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the options are -730,-701,-761,-717

Calculate enthalpy of reaction given reaction enthalpies for proposed steps in a process. K+(g) + Cl-(g) → KCI(s) KCI (LE) = ? Cl2(g) → 2CI(g) Cl-CI (BE) = 243 kJ/mol K(g) → K+(g) + 1e- K (IE) = 419 kJ/mol K(s) → K(g) K (AHsub) = 89.0 kJ/mol Cl(g) + 1e- → CI-(g) CI (EA) = -349 kJ/mol K(s) + 1/2C12(g) > KCI(s) KCI (AH;) = -436.5 kJ/mol
Transcribed Image Text:Calculate enthalpy of reaction given reaction enthalpies for proposed steps in a process. K+(g) + Cl-(g) → KCI(s) KCI (LE) = ? Cl2(g) → 2CI(g) Cl-CI (BE) = 243 kJ/mol K(g) → K+(g) + 1e- K (IE) = 419 kJ/mol K(s) → K(g) K (AHsub) = 89.0 kJ/mol Cl(g) + 1e- → CI-(g) CI (EA) = -349 kJ/mol K(s) + 1/2C12(g) > KCI(s) KCI (AH;) = -436.5 kJ/mol
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