Using the equation labels in the laboratory procedure (pictures attached), which of the following illustrates the correct calculation for DH4?a) DH4 = -DH5 + DH6 + DH7 + DH8b) DH4 = DH5 – DH6 + DH7 –DH8c) DH4 = 2 x DH5 + DH6 + DH7 – DH8d) DH4 = -DH5 + DH6 – DH7 – DH8e) None of the other answers are correctSelect one:ΔH4 = -ΔH5 + ΔH6 + ΔH7 + ΔH8 ΔH4 = ΔH5 – ΔH6 + ΔH7 –ΔH8 ΔH4 = 2 x ΔH5 + ΔH6 + ΔH7 – ΔH8 ΔH4 = -ΔH5 + ΔH6 – ΔH7 – ΔH8 None of the other answers are correct Determination of the Enthalpy of Sublimation and Decomposition of NHẠCIIn the laboratory experiment today, the heat of sublimation and decomposition of NH,Cl(s) will bedetermined. The process is represented by Equation 4.(4)NHẠC|(s) → NH38) + HCl(g)AH4 = ?Solid ammonium chloride sublimes (i.e., changes from a solid to a gas) at 340°C and decomposes togaseous ammonia and hydrogen chloride. AH4 is obtained via mathematical manipulation of fourequations and the enthalpy changes corresponding to the four related reactions:(5)NH3(ag) + HCl(aq) → NHẠC[(aq)AH5 (measured)(6)NHẠC|(s) → NHẠCl(aq)AH6 (measured)Thermodynamics.Page |2(7)NH3(g) → NH3(ag)AH7 = -34.64 kJ/mol(8)HClg) → HCl(aq)AHg = -75.13 kJ/mol

To find out the enthalpy of sublimation and decomposition of ammonium chloride in terms of the…

Answered: (4) NHẠC|(s) → NH318) + HC\6) ΔΗ4?…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Using the equation labels in the laboratory procedure (pictures attached), which of the following illustrates the correct calculation for DH4?

a) DH4 = -DH5 + DH6 + DH7 + DH8
b) DH4 = DH5 – DH6 + DH7 –DH8
c) DH4 = 2 x DH5 + DH6 + DH7 – DH8
d) DH4 = -DH5 + DH6 – DH7 – DH8
e) None of the other answers are correct

Select one:
ΔH4 = -ΔH5 + ΔH6 + ΔH7 + ΔH8
ΔH4 = ΔH5 – ΔH6 + ΔH7 –ΔH8
ΔH4 = 2 x ΔH5 + ΔH6 + ΔH7 – ΔH8
ΔH4 = -ΔH5 + ΔH6 – ΔH7 – ΔH8
None of the other answers are correct

Determination of the Enthalpy of Sublimation and Decomposition of NHẠCI
In the laboratory experiment today, the heat of sublimation and decomposition of NH,Cl(s) will be
determined. The process is represented by Equation 4.
(4)
NHẠC|(s) → NH38) + HCl(g)
AH4 = ?
Solid ammonium chloride sublimes (i.e., changes from a solid to a gas) at 340°C and decomposes to
gaseous ammonia and hydrogen chloride. AH4 is obtained via mathematical manipulation of four
equations and the enthalpy changes corresponding to the four related reactions:
(5)
NH3(ag) + HCl(aq) → NHẠC[(aq)
AH5 (measured)
(6)
NHẠC|(s) → NHẠCl(aq)
AH6 (measured)
Thermodynamics.
Page |2
(7)
NH3(g) → NH3(ag)
AH7 = -34.64 kJ/mol
(8)
HClg) → HCl(aq)
AHg = -75.13 kJ/mol

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