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+3 CO(g) 2 Fe(s) + 3 CO2(g) 3 02(g) → 2 Fe203(s) AH = -1648 kJ → 2 CO(g) + 02(g) AH= +565.4 kJ

+3 CO(g) 2 Fe(s) + 3 CO2(g) 3 02(g) → 2 Fe203(s) AH = -1648 kJ → 2 CO(g) + 02(g) AH= +565.4 kJ

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the enthalpy of reaction (AHrxn) for the following reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) Given: 4 Fe(s) + 3 02(g) → 2 Fe203(s) AH= -1648 kJ 2 CO2(g) → 2 C0(g) + 02(g) AH = +565.4 kJ
Transcribed Image Text:Calculate the enthalpy of reaction (AHrxn) for the following reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) Given: 4 Fe(s) + 3 02(g) → 2 Fe203(s) AH= -1648 kJ 2 CO2(g) → 2 C0(g) + 02(g) AH = +565.4 kJ
Expert Solution
Step 1

(1) 4Fe + 3O2----> 2Fe2O3, □H = -1648 kJ

(2) 2CO2 ----> 2CO + O2, □H = +565.4 kJ

(3) Fe2O3 + 3CO ---> 2Fe + 3CO2 

Using Hess's law, 

Reaction (3) =

-1/2×Reaction(1)  - 3/2× Reaction (2)

□H = -□H1/2 - 3□H2/2

= (1648/2) - 3 × 565.4/2

= -24.1 kJ

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