Open the activity depicting Hess's Law.**Part A**Click the "ΔH is an Extensive Property" button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2.- **Reaction 1:** \( \text{C}_8\text{H}_{18}(g) + 5\text{O}_2(g) \rightarrow 3\text{CO}_2(g) + 4\text{H}_2\text{O}(g), \, \Delta H_1 = -2043 \, \text{kJ} \)- **Reaction 2:** \( c \times 5\text{C}_8\text{H}_{18}(g) + 25\text{O}_2(g) \rightarrow 15\text{CO}_2(g) + 20\text{H}_2\text{O}(g), \, \Delta H_2 = ? \)**Express your answer to four significant figures and include the appropriate units.**- **Hint:** View Available Hint(s)**ΔH₂ =** [Value] kJ### Explanation of Diagram in ActivityThe diagram on the left includes three key points:1. **ΔH is an Extensive Property:** - This section demonstrates that the enthalpy change depends on the quantity of material present in the reaction.2. **ΔH Changes Sign When a Process is Reversed:** - This highlights that reversing a chemical equation will invert the sign of ΔH.3. **Hess's Law of Constant Heat Summation:** - The diagram visually represents how individual reactions can be algebraically summed to find the total enthalpy change. It shows that by adding or subtracting enthalpies of smaller steps, you can calculate the enthalpy change for the overall reaction. Reactions that get canceled out are marked appropriately to visualize the net equation.This exercise illustrates the fundamental concepts of Hess's Law in thermochemistry, emphasizing the calculation of enthalpy changes for chemical reactions.

Extensive Properties:-The properties of the system whose value depends upon the amount ofsubstance…

Part A Click the AH is an Extensive Property button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, AH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. Reaction 1: C3HS(g) + 502(g)→3CO2(g) +4H20(g), AĦ1 = -2043 kJ Reaction 2: 5C, Hs(g) +2502(g)→15CO2(g) + 20H2O(g), AH2 =? Express your answer to four significant figures and include the appropriate units. • View Available Hint(s) HA ? AH = Value kJ

Part A Click the AH is an Extensive Property button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, AH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. Reaction 1: C3HS(g) + 502(g)→3CO2(g) +4H20(g), AĦ1 = -2043 kJ Reaction 2: 5C, Hs(g) +2502(g)→15CO2(g) + 20H2O(g), AH2 =? Express your answer to four significant figures and include the appropriate units. • View Available Hint(s) HA ? AH = Value kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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