Use the expression below to ⚫ calculate its value and report it to the proper number of significant digits (you may need to round your answer). ⚫ calculate the % error (or % relative error or % inherent error) ⚫ calculate the absolute error. (20.54±0.02 × 0.254±0.003) / (3.21±0.05) = Value: % Error: Absolute error: ± | % (only 1 significant digit) (only 1 significant digit)

Use the expression below to ⚫ calculate its value and report it to the proper number of significant digits (you may need to round your answer). ⚫ calculate the % error (or % relative error or % inherent error) ⚫ calculate the absolute error. (20.54±0.02 × 0.254±0.003) / (3.21±0.05) = Value: % Error: Absolute error: ± | % (only 1 significant digit) (only 1 significant digit)

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter1: Basic Concepts Of Chemistry

Section: Chapter Questions

Problem 2RCYU: A student checked the accuracy of two standard top-loading balances by testing them with a standard...

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Calculate the value and report to the proper number of significant digits (you may need to round your answer). Calculate the % error (or % relative error or % inherent error) and the absolute error. (20.54+0.02 × 0.254±0.003) / (3.21±0.05) = Value: % Error: 0.1 absolute error: +3 % (only 1 significant digit) (only 1 significant digit)
Use the expression below to ⚫ calculate its value and report it to the proper number of significant digits (you may need to round your answer). ⚫ calculate the % error (or % relative error or % inherent error) ⚫ calculate the absolute error. (30.078±0.003) - (20.174±0.001) + (9.813±0.005) = Value: % Error: absolute error: ± % (only 1 significant digit) (only 1 significant digit)
Solve the value of x in the expression and express your answer in correct significant figures log ( [3.0 x 10 -2][2.0 x 10 4] / (2.0 x]3 ) = 1.347 The value of x, in correct significant figures, is
% error = (experimental value - accepted value) x 100 Accepted value Siver 10.06cm^3 -10.49cm^3 *100 / 10.49 Is this correct ?
4
Can you help me answer this questions 4 and 5, this is from the previous question I just split my question, thanks
The relative error for the following data below is: 39.63, 39.61, 39.05, 39.08 (the true accepted value= 40.00) Please fill in the space with a numerical value with two digits, without any unit and including sign (-) or (+).
I don't understand the wording. The least significant digit means the last digit? 7.700 X 2.1 = 16.17 would the uncertainty be 0.01 ? 2.132 + 17 + 4.04 = 23.172 would the uncertainty be 0.001 ?
Please answer.
Find the difference between the value of x2 and the sum of x1 plus x3.; let x4 be equivalent to the sum of x1 and x3 and let x5 be the difference between x2 and x5. This calculation scheme is shown below. Make notes about any similarities or differences between the values in your notes. x4 = x1 + x3 x5 = x2 – x4 Data Analyis This section will include all data collected during the lab. Thermochemical Data Tinitial (°C) Tfinal (°C) ΔT (°C) moles NaOH qreaction (kJ) ΔHrxn Reaction 1 25.0 30.3 +5.3 0.025 -1.11 -44.4 Reaction 2 25.0 37.0 +12.0 0.025 -2.51 -100.4 Reaction 3 25.0 31.7 +6.7 0.025 -1.40 -56.1 Reaction 1: NaOH(s) → Na+(aq) + OH-(aq) + x1 kJ 1g /39.977g/mol = 0.025 moles Moles NaOH = 0.025 qsolution = (4.184 J/g °C) (50.0g) (30.3°C -25.0°C) = -1108.76 J/ 1000 qreaction (kJ) = -1.11 kJ ΔH = -1.11 kJ/ 0.025 moles ΔHrxn = -44.4 kJ/mol…
What is the smallest mass that we can measure on an analytical balance that has a tolerance of ±0.1 mg, if the relative error must be less than 0.1%?
What is the error in the answer to the following? a) (22.10 ± 0.01) + (37.51 ± 0.02) = b) (30.88 ± 0.03) - (31.57 ± 0.06) = c) (5.88 ± 0.05) × (2.17 ± 0.01) =