Use Kirchhoff's rules with matrix solution to calculate currents I1, I2, and I3, and compare them with the experimental results in tabular form. This image depicts an electrical circuit schematic that includes three resistors, two voltage sources, and three current flows. Here's a detailed explanation:### Circuit Components:1. **Voltage Sources:** - **5.00V Source:** Positioned on the left side of the circuit, marked with a positive and negative terminal. - **4.00V Source:** Placed on the right side, also marked with positive and negative terminals.2. **Resistors:** - **R₁ = 50Ω:** Connected vertically below the 5.00V source. - **R₂ = 25Ω:** Placed below the 4.00V source. - **R₃ = 75Ω:** Located in the middle, connected to both above-mentioned resistors.3. **Currents:** - **I₁ = 0.029A:** Current flows upward from the 5.00V source through R₁. - **I₂ = 0.019A:** Current flows upward from the 4.00V source through R₂. - **I₃ = 0.047A:** Current flows upward through R₃.### Analysis:- The circuit is divided into two loops, numbered as 1 and 2. - Loop 1 includes the 5.00V source and R₁.- Loop 2 consists of the 4.00V source and R₂.- The combined current flowing through R₃ indicates the interaction and sum of currents I₁ and I₂ in the circuit, representing Kirchhoff’s Current Law.This diagram is an educational representation to help visualize and understand the relationships between voltage, current, and resistance in a circuit.

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Use Kirchhoff's rules with matrix solution to calculate currents I1, I2, and I3, and compare them with the experimental results in tabular form.

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