LAQ 3. In the circuit below, there are four branches; the top branch is branch number one that has the ammeter and the resistor R. Take I to be the current going through the ammeter from left to right in branch one. Take It to be the current that leaves the battery AV from the positive end and the current Iz the one that goes through the 5.00- 2 resistor from right to left, in the third branch. Notice the symmetry dealing with the resistor R on the top branch and lowest branch (fourth branch). What are the expected readings of the following in the figure below? (R = 6.20 2, AV = 6.50 V) (b) ammeter (Give your answer in mA.) voltmeter (Give your answer in volts.) A 10.00 www www R AV V ww + R 4.50 V www 5.00 What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? In this part, take I, the current going through the ammeter from left to right. Take I: the current that leaves the battery AV from the positive end and the current Iz going through the 5.00-Q resistor from left to right.
LAQ 3. In the circuit below, there are four branches; the top branch is branch number one that has the ammeter and the resistor R. Take I to be the current going through the ammeter from left to right in branch one. Take It to be the current that leaves the battery AV from the positive end and the current Iz the one that goes through the 5.00- 2 resistor from right to left, in the third branch. Notice the symmetry dealing with the resistor R on the top branch and lowest branch (fourth branch). What are the expected readings of the following in the figure below? (R = 6.20 2, AV = 6.50 V) (b) ammeter (Give your answer in mA.) voltmeter (Give your answer in volts.) A 10.00 www www R AV V ww + R 4.50 V www 5.00 What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? In this part, take I, the current going through the ammeter from left to right. Take I: the current that leaves the battery AV from the positive end and the current Iz going through the 5.00-Q resistor from left to right.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:LAQ 3.
In the circuit below, there are four branches; the top
branch is branch number one that has the ammeter and the resistor R.
Take I to be the current going through the ammeter from left to right in
branch one. Take It to be the current that leaves the battery AV from
the positive end and the current Iz the one that goes through the 5.00-
2 resistor from right to left, in the third branch. Notice the symmetry
dealing with the resistor R on the top branch and lowest branch (fourth
branch). What are the expected readings of the following in the figure
below? (R = 6.20 2, AV = 6.50 V)
(b)
ammeter (Give your answer in mA.)
voltmeter (Give your answer in volts.)
A
10.00
www
www
R
AV
V
ww
+
R
4.50 V
www
5.00
What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change
if the 4.50 V battery was flipped so that its positive terminal was to the right? In this part, take I,
the current going through the ammeter from left to right. Take I: the current that leaves the
battery AV from the positive end and the current Iz going through the 5.00-Q resistor from left to
right.
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