A 2.20 mF capacitor initially has charge 4.20 mC. You connect it in series with a 4.00 MΩ resistor and an open switch. If t = 0 is the time when you close the switch, (a) at what time will the capacitor charge be 1.20 mC and (b) what will be the current in the circuit at this time?
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A: Step 1:
A 2.20 mF capacitor initially has charge 4.20 mC. You connect
it in series with a 4.00 MΩ resistor and an open switch. If t = 0 is the
time when you close the switch, (a) at what time will the capacitor charge
be 1.20 mC and (b) what will be the current in the circuit at this time?
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- Problem 8: A capacitor of capacitance C-10 uF has been charged so that the potential difference between its plates is Vo 380 V. The capacitor is then connected to a resistor of resistance R-6.5 k2. The switch S is closed, and the capacitor begins to discharge Randomized Variables Vo 380 V l- ©theexpertta.com Δ Part (a) Calculate the time constant of the circuit in seconds. tan() cos0) cotanasin) acos(0 atan() acotan sinh() cosh)tanh cotanh) O Degrees O Radians sin HOME 4 5 6 0 BACKSPACE CLEAR Submit Hint I give up! Hints: 1%, deduction per hint. Hints remaining: 2 Feedback: 1% deduction per feedback. a Part (b) Calculate the charge Qo on the capacitor before the switch is closed, in coulombs. Part (c) Calculate the current Io immediately after the switch is closed, in amperes. . Part (d) Calculate the potential difference VC in volts between the capacitor plates at time t - 5.0 ms after the switch is closed A Part (e) Calculate the time T in s after which the charge on the capacitor…A fully charged RC circuit is set up using R = 15.0 Ω and C = 8.20 μF with the switch initially open, as shown in the figure. At a certain time after the switch is closed, the current in the circuit has magnitude 3.00 A and the charge on the capacitor is 30.0 μC. At this time, what is the rate at which energy is being stored in the capacitor (in W)?The figure below shows a capacitor, with capacitance C = 45.0 µF, and a resistor, with resistance R = 60.0 kN, connected in series to battery, with & = 15.0 V. The circuit has a switch, which is initially open. R (a) What is the circuit's time constant (in s)? (b) After the switch is closed for one time constant, how much charge (in C) is on the capacitor?
- The capacitor with capacitance C₁ initially carries a charge Q (see figure below). While, the capacitor with capacitance C₂ is initially uncharged. The switch S is closed at time t = 0, and the charges begin to flow in the circuit. Find the charge flown through the wires as a function of time, q(t). QC₁ A) (0) (1 - e-(C₁+C₂)t/RC₁C₂) C₁+C₂ B) (02₂) (1 - e-(C₁+C₂)t/RC₁C₂) C₁+C₂ QC₁ C₂ C) (043) (1 — e¯(C₁+C₂)t/RC₂C₂) D) Q(1 + e-(₁+₂)t/RC1C₂) E) None of the above. +Q C₁ R C₂The following equations describe an electric circuit. −I1(247 Ω) + 5.80 V − I2(381 Ω) = 0 I2(381 Ω) + I3(150 Ω) − 3.10 V = 0 I1 + I3 − I2 = 0 Calculate the unknowns (in mA). With respect to the 5.8 V battery, consider current moving toward the positive pole as positive and current moving toward the negative pole as negative. THE FOLLOWING GIVEN ANSWERS WERE INCORRECT: I1= -10.008 mA I2= -0.868 mA I3= 0.139 mAA 2.00-nF capacitor with an initial charge of 4.98 ?C is discharged through a 1.31-kΩ resistor. (a) Calculate the magnitude of the current in the resistor 9.00 ?s after the resistor is connected across the terminals of the capacitor. mA(b) What charge remains on the capacitor after 8.00 ?s? ?C(c) What is the maximum current in the resistor? A
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